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Leya [2.2K]
2 years ago
9

A mixture of NO2 and N2O4 gas is at equilibrium in a closed container. These gases react with the equation 2NO2 ⇌ N2O4. What wil

l happen if the size of the container is increased?
Chemistry
1 answer:
AnnZ [28]2 years ago
3 0

Answer:

Equilibrium shifts left making more NO2

Explanation:

In Le Chatlier's Principle,  increase in volume  shifts equilibrium to side with more moles so... there's 2 moles on left and 1 mole on right, so equilibrium shifts to left making more NO2

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A weak bond called a ______ bond results from an attraction between a slightly positive region in a molecule and a slightly nega
tamaranim1 [39]

<u>Answer:</u> The weak bond having slightly positive region and a slightly negative region is polar covalent bond.

<u>Explanation:</u>

Covalent bond is defined as the bond which is formed by the sharing of electrons between the atoms. <u>For Example:</u> HCl, CH_4 etc..

They are of two types:

  • <u>Polar covalent bond:</u> This bond is formed when difference in electronegativity between the atoms is present. When atoms of different elements combine, it results in the formation of polar covalent bond.

In this bond, a dipole is created. More electropnegative atom will have a slight negative charge and less electronegative atom will have a slight positive charge. For Example: CO_2,NO_2 etc..

  • <u>Non-polar covalent bond:</u> This bond is formed when there is no difference in electronegativity between the atoms. When atoms of the same element combine, it results in the formation of non-polar covalent bond. For Example: N_2,O_2 etc..

Hence, the weak bond having slightly positive region and a slightly negative region is polar covalent bond.

7 0
3 years ago
Plz someone help, really struggling
frez [133]

Answer:

22.9 Liters CO(g) needed

Explanation:

2CO(g)     +   O₂(g)    =>    2CO₂(g)

? Liters          32.65g

                 = 32.65g/32g/mol

                 =   1.02 moles O₂

Rxn ratio for CO to O₂ = 2 mole CO(g) to 1 mole O₂(g)

∴moles CO(g) needed = 2 x 1.02 moles CO(g) = 2.04 moles CO(g)

Conditions of standard equation* is STP (0°C & 1atm) => 1 mole any gas occupies 22.4 Liters.

∴Volume of CO(g) = 1.02mole x 22.4Liters/mole = 22.9 Liters CO(g) needed

___________________

*Standard Equation => molecular rxn balanced to smallest whole number ratio coefficients is assumed to be at STP conditions (0°C & 1atm).

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