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jenyasd209 [6]
2 years ago
13

Solve the expression (7th grade math): -0.8m+3-12.5m+95.36m

Mathematics
1 answer:
Lana71 [14]2 years ago
7 0

Step-by-step explanation:

<u>Combine Like-Terms:</u>

-0.8m + 3 - 12.5m + 95.36m

-13.3m + 3 + 95.36m

82.06m + 3

82.06m + 3 is your simplified expression.

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Lines m and n are parallel solve for the following values of x. Tell which theorem you used.
nevsk [136]

Answer:

x=60°

Step-by-step explanation:

angle 135° and (2x+15)° are corresponding and thus are equal

Therefore (2x+15)°=135°

2x=135-15

2x=120°

X=60°

8 0
3 years ago
Are these angles complementary, supplementary, or neither?
SashulF [63]
I would say complementary because the angle degrees are the same
4 0
3 years ago
What is the total amount that First Consumer Bank will receive after lending Jane $7,000 for three years at an interest rate of
nlexa [21]
<span>In 3 years, you will have $8,103.38

Formula:
</span>

<span>A = P (1 + r/n)<span> ^(nt)</span></span>

Where:

A = the future value of the investment/loan, including interest
P = the principal investment amount (the initial deposit or loan amount)
r = the annual interest rate (decimal)
n = the number of times that interest is compounded per year
t = the number of years the money is invested or borrowed for

7 0
3 years ago
Given sin thata = 2/5 and 0° &lt; thata &lt; 90°. find sin 2 thata​
Andrej [43]

Recall the double angle identity:

\sin2\theta=2\sin\theta\cos\theta

With \theta measuring between 0º and 90º, we know \cos\theta>0. So from the Pythagorean identity, we get

\sin^2\theta+\cos^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\dfrac{\sqrt{21}}5

Then

\sin2\theta=2\dfrac25\dfrac{\sqrt{21}}5=\dfrac{4\sqrt{21}}{25}

5 0
3 years ago
Please help thank you! will give brainliest!
VashaNatasha [74]

A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3). This can be obtained by putting the ΔABC's vertices' values in (x, y-3).

 

<h3>Calculate the vertices of ΔA'B'C':</h3>

Given that,

ΔABC : A(-6,-7), B(-3,-10), C(-5,2)

(x,y)→(x,y-3)

The vertices are:

  • A(-6,-7 )⇒ (-6,-7-3) = A'(-6, -10)
  • B(-3,-10) ⇒ (-3,-10-3) = B'(-3,-13)
  • C(-5,2) ⇒ (-5,2-3) = C'(-5,-1)

Hence A'(-6, -10), B'(-3,-13), and C'(-5,-1) are the vertices of the ΔA'B'C' under the translation rule (x,y)→(x,y-3).

Learn more about translation rule:

brainly.com/question/15161224

#SPJ1

7 0
2 years ago
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