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sashaice [31]
2 years ago
10

In which collision scenario is the difference in total momentum before and total momentum after the collision the greatest?

Physics
1 answer:
Hitman42 [59]2 years ago
8 0

Answer:

The law states that when two objects collide in a closed system, the total momentum of the two objects before the collision is the same as the total momentum of the two objects after the collision. The momentum of each object may change, but the total momentum must remain the same.

Explanation:

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How should Tika most likely describe this relationship between force and distance to her study group
omeli [17]

Answer:

Force is work done divided by distance

Explanation:

Work done to an object is given as rhe product of force and diatance moved, hence expressed as W=Fd where F is the applied force in Newtons, d is diatance moved in meters and W is work. The relationship between force and distance then is found by making either F or d the subject hence

F=\frac {W}{d}\\d=\frac {W}{F}

hence we can say that distance is given by dividing work by force or alternatively Force is relates to distance by dividing work done by distance. Both are correct.

7 0
3 years ago
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How does Kinetic Energy and the Law of Conservation of Momentum apply to inelastic<br> collisions?
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Answer:

Explanation:

An inelastic collision is one in which the internal kinetic energy changes (it is not conserved) . The two objects come to rest after sticking together, conserving momentum. But the internal kinetic energy is zero after the collision.

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2 years ago
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Einstein developed much of his understanding of relativity through the use of gedanken, or thought, experiments.
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True. Thought experiments are what he called them, it’s like meditation
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3 years ago
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Story on where there is a will there's a way<br>​
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Lol what i think i’ve heard of that story
4 0
4 years ago
The half-life of plutonium 239 is 24,200 years. Assume that the decay rate is proportional to the amount. Determine the amount o
kotykmax [81]

Answer:

time taken is equal to 14,156 years

Explanation:

we know,

Y=Ae^{-kt}

at t = 0

Y(0) = A

given that half life of plutonium 239 = 24,200

\dfrac{A}{2}=Ae^{-kt}\\0.5=e^{-kt}\\k\times 24200 = ln(2)\\k = \dfrac{ ln(2)}{24200}

Y=Ae^{-kt}

\frac{3}{2} = e^{-kt}\\ln(1.5)=-\dfrac{ ln(2)}{24200}\times t\\t=-\dfrac{ln(1.5)\times 24200}{ ln(2)}\\t=14,156 \ years

hence time taken is equal to 14,156 years

5 0
3 years ago
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