Answer:
The magnitude of the new electric field is <u>35820 N/C</u>.
Explanation:
Given:
Original magnitude of electric field (E₀) = 2388 N/C
Original voltage = 'V' (Assume)
Original separation between the plates = 'd' (Assume)
Now, new voltage is three times original voltage. So, 
New distance is 1/5 the original distance. So, 
Now, electric field between the parallel plates originally is given as:
Let us find the new electric field based on the above formula.
Now, 
. So,
Therefore, the magnitude of the new electric field is 35820 N/C.
Answer:
<h2>the car must move with the speed</h2><h2>
</h2>
Explanation:
As we know that the momentum of the car and truck is same
so as per the formula of momentum we have
so we have
so we will have
So the car must move with the speed
Answer:
Review each answer in the explanation part
Explanation:
Identify a problem or need = Aerospace engineers need a lightweight material to build a jet
Note: Identify a problem is related always with a need.
After identify the problem the next stage is the design
Design a solution = Engineers determine what features the material must have.
Note: The design process implies the choice of the materials and the proper numeric calculations.
Implement the solution = Engineers test a carbon - plastic compound in a wind tunnel.
Note: after the design, the following process is the built of the equipment and the different tests.
Evaluate the solution = The carbon-plastic compound is redesigned to save maximun energy.
Note: After testing, you enter a part of re-design that means making improvements to the already constructed.
Answer:
a. 32.67 rad/s² b. 29.4 m/s²
Explanation:
a. The initial angular acceleration of the rod
Since torque τ = Iα = WL (since the weight of the rod W is the only force acting on the rod , so it gives it a torque, τ at distance L from the pivot )where I = rotational inertia of uniform rod about pivot = mL²/3 (moment of inertia about an axis through one end of the rod), α = initial angular acceleration, W = weight of rod = mg where m = mass of rod = 1.8 kg and g = acceleration due to gravity = 9.8 m/s² and L = length of rod = 90 cm = 0.9 m.
So, Iα = WL
mL²α/3 = mgL
dividing through by mL, we have
Lα/3 = g
multiplying both sides by 3, we have
Lα = 3g
dividing both sides by L, we have
α = 3g/L
Substituting the values of the variables, we have
α = 3g/L
= 3 × 9.8 m/s²/0.9 m
= 29.4/0.9 rad/s²
= 32.67 rad/s²
b. The initial linear acceleration of the right end of the rod?
The linear acceleration at the initial point is tangential, so a = Lα = 0.9 m × 32.67 rad/s² = 29.4 m/s²
