Using the Pythagorean Theorem, we have x^2+(x+2)^2=51^2, and
x^2+ x^2+4x+4=2x^2+4x+4=51^2. After that, we subtract 51^2 from both sides to get 2x^2+4x-2597. Using the quadratic formula (x=(-b+-sqrt(b^2-4ac))/2a in ax^2+bx+c), we get around 35 for x. We did + instead of minus after b due to that it can't be negative! x+2=37, so you save 35+37-51=around 21 feet
Answer:
Step-by-step explanation:
Hey there! :D
1. c - 7 = 32
To solve this problem, add the difference and the subtrahend of the given equation.
Checking:
To check, simply substitute the conclusion on the unknown quantity.
39 (c) - 7 = 32
Thus, the equation was correct which gives us the answer that:
2. r + 4 = 39
To solve this problem, subtract the sum and the addend of the given equation.
Checking:
To check, simply substitute the conclusion on the unknown quantity.
35 (r) + 4 = 39
Thus, the equation was correct which gives us the answer that:
Answer:
a= 200
b = 210
Step-by-step explanation:
My assumption is, we have to find the length of sides of rectangle
Given
perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)
area = a*b = 42,000 ft^2 (ii)
from eq (1)
2a + 2b = 820
=> 2(a+b) = 820
=> a+b = 820/2
=> a + b = 410
=> a = 410-b (iii)
putting the value of a in eq(ii), we get
(410-b) *b = 42,000
410b - b^2 = 42,000
0 = b^2 - 410b + 42000
b^2 - 410b + 42000 = 0
b^2- 200b- 210b + 42000 = 0
b(b-200)-210(b-200) = 0
(b-200)(b-210) = 0
or
b= 210 and b = 200
if b is larger side than b =210
By putting value of b in eq(iii),
a = 410 -210 = 200
