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Nana76 [90]
2 years ago
7

Why does this atom not want to share, lose, or gain electrons?

Chemistry
1 answer:
ki77a [65]2 years ago
4 0
So it won’t become unstable!
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The process of change in a population over time is called what?
guapka [62]

Answer:

Microevolution

8 0
3 years ago
If you had excess aluminum, how many moles of aluminum chloride could be produced from 28.0 g of chlorine gas, Cl2?
Mice21 [21]

Answer:

Yes chemistry. Try to add then multiply the top. Get the moles and you will find it.

Explanation:

Try to add then multiply the moles in the equation

6 0
3 years ago
What are the products when ammonia (NH3) decomposes according to this equation?<br> NH3
In-s [12.5K]
<span>Ammonia (NH3) is the combination of Nitrogen and Hydrogen elements.
=> N2 + 3H2 => 2NH3

Ammonia is basically used as a fertilizer. It is a gas composed of nitrogen and hydrogen. It is colorless with strong odor. Here are some other uses of Ammonia aside from fertilizer:
=> used by manufacturer to produce synthetic fiber
=> Used in metallurgical process
Ammonia can be decomposed easily and it produce hydrogen that is very convenient in welding.
Ammonia’s boiling point is -28.03 F and freezing point is -107.8F.



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7 0
2 years ago
a closed flask of air (0.250 L) contains 5.00 "puffs" of particles. The pressure probe on the flask reads 93 kPa. A student uses
Sergio039 [100]

Answer: New pressure inside the flask would be 148.8 kPa.

Explanation: The combined gas law equation is given by:

PV=nRT

As the flask is a closed flask, so the volume remains constant. Temperature is constant also.

So, the relation between pressure and number of moles becomes

P=n\\or\\\frac{P}{n}=constant

\frac{P_1}{n_1}=\frac{P_2}{n_2}

  • Initial conditions:

P_1=93kPa\\n_1=5\text{ puffs}

  • Final conditions: When additional 3 puffs of air is added

P_2=?kPa\\n_2=8\text{ puffs}

Putting the values, in above equation, we get

\frac{93}{5}=\frac{P_2}{8}\\P_2=148.8kPa

3 0
2 years ago
A sample of gas has a volume of 3.75 L at a temperature of 25°C and a pressure of 1.15 atm. What will the volume be at a tempera
omeli [17]

Answer: V = 5.1 L

Explanation: To find the new volume, we will use the formula of Combined Gas Law and derive V2. We also need to convert first the temperature in Kelvin and convert torr to atm ( 1 atm = 760 torrs ).

Solution attached.

5 0
2 years ago
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