Answer:
375 km
Explanation:
Using the equation, d = vt, we simply plug in the numbers:
v = 150 km/hr
t = 2.5 h
d = (150 km/hr)*(2.5 h)
d = 375 km
Answer:
mass flow rate at water condenses is 36.72 kg/min
Explanation:
given data
temperature t1 = 38°C
temperature t2 = 14°C
humidity ∅= 97 % = 0.97
rate v = 510 m³/min
to find out
mass flow rate at water condenses
solution
by gas equation we find here mass flow rate that is
pv = mRT
put here value and p is 0.066626 bar at 38°C and find m
m = 0.06626 × 
× 510 / 287×311
m = 37.85 kg/min
so at water condenses mass flow rate is express as
∅ = M / m
Mass flow rate M = ∅ × m
M = 0.97 × 37.85
mass flow rate = 36.72 kg/min
so mass flow rate at water condenses is 36.72 kg/min
If an object<span> has a net </span>force<span> acting on it, it will accelerate. The </span>object<span> will speed up, slow down or change direction. An </span>unbalanced force<span> (net </span>force<span>) acting on an </span>object<span>changes its speed and/or direction of motion. An </span>unbalanced force<span> is an unopposed</span>force<span> that causes a change in motion.
thus the car would get its speed, and or direction mixed up</span>
Answer:
2.61 J
Explanation:
Since potential energy U = mgy where m = mass of object, g = acceleration due to gravity = 9.8 m/s² and y = height of object above the ground.
Now for the coffee mug, m= 0.422 kg and it is 0.63 m on a table, so it is 0.63 m above the ground. Thus, y = 0.63 m.
We compute U
U = mgy
= 0.422 kg × 9.8 m/s² × 0.63 m
= 2.605 J
≅ 2.61 J
So, the potential energy of the mug with respect to the floor is 2.61 J
The boat is initially at equilibrium since it seems to start off at a constant speed of 5.5 m/s. If the wind applies a force of 950 N, then it is applying an acceleration <em>a</em> of
950 N = (2300 kg) <em>a</em>
<em>a</em> = (950 N) / (2300 kg)
<em>a</em> ≈ 0.413 m/s²
Take east to be positive and west to be negative, so that the boat has an initial velocity of -5.5 m/s. Then after 11.5 s, the boat will attain a velocity of
<em>v</em> = -5.5 m/s + <em>a</em> (11.5 s)
<em>v</em> = -0.75 m/s
which means the wind slows the boat down to a velocity of 0.75 m/s westward.
