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joja [24]
3 years ago
10

Adam takes a bus on a school field trip. The bus route is split into the five legs listed in the table. Find the average velocit

y for each leg of the trip. Then arrange the legs of the trip from highest velocity to lowest. Leg Distance (km) Time (min) A 18 9 B 25 15 C 24 8 D 48 12 E 15 7 leg A leg B leg C leg D leg E
Physics
1 answer:
Bogdan [553]3 years ago
3 0

Answer:

The answer is:

VA= 33 m/S

VB= 27.8 m/s

VC= 50 m/s

VD=66.7 m/s

VE=35.7 m/s

So, the Legs from the highest velocity to the lower are:

D - C - E - A - B

The explanation:

we are going to use the velocity formula:

Velocity = distance (m) / time (s)

So,

A) when D = 18 Km = 18000 m

and t = 9 min = 9*60 =540 s

So V = 18000m/ 540 S

      = 33 m/S

B) when D = 25 Km = 25000 m

and t = 15 min = 15 * 60 = 900 S

So V = 25000m / 900S

     = 27.8 m/s

C) when D = 24 Km = 24000 m

and t = 8 min = 8 * 60 = 480 s

So V = 24000m / 480s

     = 50 m/s

D) when D = 48 Km = 48000 m

and t = 12 min = 12 * 60 = 720 s

So V = 48000 m / 720s

       =66.7 m/s

E) when D = 15 km = 15000m

and t = 7 min = 7 * 60 = 420 s

So V = 15000m / 420s

      = 35.7 m/s

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