Answer:
<u>○</u><u>MONOPOLY</u><u> </u><u>○</u>
○1▪︎Monopoly is the type of imperfect competition where a seller or producer captures the majority of market share due to lack of substitutes or competitors.○
○2▪︎Nil competition exists as only one seller present in the market.○
<u>○</u><u>MONOPOLISTIC</u><u> </u><u>○</u>
○1▪︎Monopolistic competition is a type of imperfect competition where many sellers try to capture market share by differentiating their products.○
○2▪︎Very high competition exists as there are many sellers.○
Answer:
See below
Explanation:
PV = n RT R = .082057 L - Atm / (K-Mole)
.97 V = .118 (.082057)(305)
V = 3.04 liters
Will not change for argon.....will be the same for all ideal gases
Explanation:
<h2>Radium(Ra)=> </h2>
atomic number=88
<h2>BERYLLIUM (Be)=></h2>
atomic number =4
why is Ra larger than Be
<h3>1. since the atomic number of Ra is greater than Be, the number of electrons is more, which means there are more number of shells present in Ra than Be. </h3><h2>(atomic Radius)</h2>
<h2>2. the more the valence electron (excluding fully filled ones) the less is the nuclear attraction force</h2><h3>since Ra has more valence electron in its outermost shell, the nuclear attraction force is less which means that Ra 's size is greater than Be.</h3>
hope it helps:)
8moles of SO_2 need 11mol O_2
Moles of sO_2
So
Moles of O_2
We know
- 1mol at STP=22.4L
- 1.4mol=0.14(22.4)=3.13L O_2
Answer: 160 ml
Explanation:
The expression used will be :
where,
= concentration of Ist alcohol solution= 10%
= concentration of 2nd alcohol solution= 55%
= volume of Ist alcohol solution = 200 ml
= volume of 2nd alcohol solution= v ml
= concentration of resulting alcohol solution= 30%
= volume of resulting alcohol solution= (v+200) ml
Now put all the given values in the above law, we get the volume of added.
By solving the terms, we get :
Therefore, the volume of 55% mixture needed to be added to obtain the desired solution is 160 ml.
