All categories

3 years ago

Anyone from kerala?what is gravitation

Physics

2 answers:

ladessa [460]3 years ago

7 0

Answer:

1)Yes

2)gravitation, in mechanics the universal force of attraction acting between all matter. ... On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them. Gravity is measured by the acceleration that it gives to freely falling object

Explanation:

Darya [45]3 years ago

3 0

Answer:

i am from kerala.

gravitation means movement, or a tendency to move, towards a centre of gravity, as in the falling of bodies to the earth.

Explanation:

You might be interested in

The sun is more massive than the moon, but the sun is farther from the earth. Which one exerts a greater gravitational force on

love history [14]

Answer:

178.4 times

Explanation:

We have Newton formula for attraction force between 2 objects with mass and a distance between them:

$F_G = G\frac{M_1M_2}{R^2}$

where $G =6.67408 × 10^{-11} m^3/kgs^2$ is the gravitational constant on Earth. $M_1, M_2$ is the masses of the 2 objects. and R is the distance between them.

From here we can calculate the ratio of gravitational force between the moon and the sun

$\frac{F_s}{F_m} = \frac{G\frac{MM_s}{R_s^2}}{G\frac{MM_m}{R_m^2}}$

We can divide the top and bottom by G and M

$\frac{F_s}{F_m}= \frac{M_s}{R_s^2}:\frac{M_m}{R_m^2}$

$= \frac{M_s}{R_s^2}\frac{R_m^2}{M_m}$

$= \frac{M_s}{M_m}(\frac{R_m}{R_s})^2$

$= \frac{1.99*10^{30}}{7.35*10^{22}}(\frac{3.85*10^8}{1.5*10^{11}})^2$

$= 27074830*6.59*10^{-6} = 178.4$

So the gravitational force of the sun is about 178 times greater than that of the moon to an object on Earth

5 0

3 years ago

A particle travels in a circular orbit of radius 21 m. Its speed is changing at a rate of 23.1 m/s2 at an instant when its speed

Yuri [45]

The particle has an acceleration vector with one component directed toward the center of its orbit, and the other directing tangentially to its orbit. Call these components $\vec a_c$ ( $c$ for center) and $\vec a_t$ ( $t$ for tangent). Then its acceleration vector has magnitude

$|\vec a|=\sqrt{\|\vec a_c\|^2+\|\vec a_t\|^2}$

We have

$\|\vec a_c\|=\dfrac{\|\vec v\|^2}r$

where $\|\vec v\|$ is the particle's speed and $r$ is the radius of orbit, so

$\|\vec a_c\|=\dfrac{\left(37.2\frac{\rm m}{\rm s}\right)^2}{21\,\rm m}=65.9\dfrac{\rm m}{\mathrm s^2}$

We're given that the particle's speed changes at a rate of 23.1 m/s^2. Its velocity vector points in the same direction as $\vec a_t$ , i.e. perpendicular to $\vec a_c$ , so

$\|\vec a_t\|=23.1\dfrac{\rm m}{\mathrm s^2}$

Then the magnitude of the particle's acceleration is

$\|\vec a\|=\sqrt{\left(65.9\dfrac{\rm m}{\mathrm s^2}\right)^2+\left(23.1\dfrac{\rm m}{\mathrm s^2}\right)^2}=\boxed{69.8\dfrac{\rm m}{\mathrm s^2}}$

7 0

3 years ago

If you dribble a basketball with a frequency of 1.77 Hz, how long does it take for you to complete 12 dribbles?

Licemer1 [7]

<h2>It takes 6.78 seconds to complete 12 dribbles.</h2>

Explanation:

Frequency of dribble = 1.77 Hz

That is

Number of dribbles in 1 second = 1.77

$\texttt{Time taken for 1 dribble = }\frac{1}{1.77}=0.565s$

Now we need to find how long does it take for you to complete 12 dribbles.

Time taken for 12 dribbles = 12 x Time taken for 1 dribble

Time taken for 12 dribbles = 12 x 0.565

Time taken for 12 dribbles = 6.78 seconds

It takes 6.78 seconds to complete 12 dribbles.

8 0

3 years ago

A bicyclist is in a 50-km race. He says he had an average velocity of 35. What is missing in the cyclist’s velocity? A. units on

aleksandr82 [10.1K]

A. Units
the rest can be understand that he did not clarify

5 0

4 years ago

I will mark you brainlist. What is the relationship between Motion and Speed?

scoundrel [369]

Answer:

Motion is a combination of acceleration and velocity(speed). Speed is distance travelled/ time taken. Miles per hour for example. Acceleration is the change in velocity in the time frame of the velocity.

6 0

3 years ago

Read 2 more answers