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3 years ago

Divide. Show your work.

Mathematics

1 answer:

pickupchik [31]3 years ago

7 0

I stopped after 3 decimals, but the answer I got was 301.176

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Find the student's error in solving the following

zheka24 [161]

x>7

Step-by-step explanation:

when dividing by a (-)

the inequality sign changes

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2 years ago

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Freddy has a shelf that is 72/5 inches wide. How many catalogs can freddy arrange on the shelf if each catalog is 4/5 of an inch

Leni [432]

Hey!

72/5 ÷ 4/5

All you have to do is divide 72 by 4 because the denominator is the same.

72 ÷ 4 = 18

Answer ⇒ 18 catalogs

Hope this helps! :)

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3 years ago

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1. Lisa is working with the system of equations x + 2y = 7 and 2x ‒ 5y = 5. She multiplies the first equation by 2 and then sub

Musya8 [376]

All methods are supposed to be correct in most if not all situations and it should not matter if you use a different method given the options

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3 years ago

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A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

A jewelry store marks up the price of its jewelry up 50%. What will be the selling price of an item that the store purchased for

snow_tiger [21]

Answer: $142.5

Step-by-step explanation: If the price is being marked up by 50%, you take 50% or half of the original price of $95, which is 47.5, and add it to your original price.

95 + 47.5 = 142.5

3 0

2 years ago