The answer to your equation is c
Answer:
1. The compound should be dissolved at the solvent boiling point.
2. It should be better none of the compound dissolve while at room
temperature.
3. The compound must have lower boiling point (low boiling point) than
melting point in hot solvent so to avoid it melts.
4. The compound have different solubility and impurity.
Explanation:
in order a compound to have a good crystallization, these are the primary consideration that should be followed.
1. The compound should be dissolved at the solvent boiling point.
2. It should be better none of the compound dissolve while at room
temperature.
3. The compound must have lower boiling point (low boiling point) than
melting point in hot solvent so to avoid it melts.
4. The compound have different solubility and impurity.
Answer:
11025 N / m²
Explanation:
Los siguientes datos se obtuvieron de la pregunta:
Área (A) = 400 cm²
Masa (m) = 45 Kg
Aceleración por gravedad (g) = 9,8 m / s²
Presión (P) =?
A continuación, determinaremos la fuerza aplicada. Esto se puede obtener de la siguiente manera:
Masa (m) = 45 Kg
Aceleración por gravedad (g) = 9,8 m / s²
Fuerza (F) =.?
F = m × g
F = 45 × 9,8
F = 441 N
A continuación, convertiremos 400 cm² a m². Esto se puede obtener de la siguiente manera:
1 cm² = 0,0001 m²
Por lo tanto,
400 cm² = 400 cm² × 0,0001 m² / 1 cm²
400 cm² = 0,04 m²
Por tanto, 400 cm² equivalen a 0,04 m².
Finalmente, determinaremos la presión ejercida de la siguiente manera:
Área (A) = 0.04 m².
Fuerza (F) = 441 N
Presión (P) =?
P = F / A
P = 441 / 0,04
P = 11025 N / m²
Por tanto, la presión ejercida es 11025 M / m²
The height of the roof is <u>3.57m</u>
Let the drops fall at a rate of 1 drop per t seconds. The first drop takes 5t seconds to reach the ground. The second drop takes 4t seconds to reach the bottom of the 1.00 m window, while the 3rd drop takes 3t s to reach the top of the window.
Calculate the distances traveled by the second and the third drops s₂ and s₃, which start from rest from the roof of the building.
![s_2=\frac{1}{2} g(4t)^2=8gt^2\\ s_3=\frac{1}{2} g(3t)^2=(4.5)gt^2](https://tex.z-dn.net/?f=s_2%3D%5Cfrac%7B1%7D%7B2%7D%20g%284t%29%5E2%3D8gt%5E2%5C%5C%20%20s_3%3D%5Cfrac%7B1%7D%7B2%7D%20g%283t%29%5E2%3D%284.5%29gt%5E2)
The length of the window s is given by,
![s=s_2-s_3\\ (1.00 m)=8gt^2-4.5gt^2=3.5gt^2\\ t^2=\frac{1.00 m}{(3.5)(9.8m/s^2)} =0.02915s^2](https://tex.z-dn.net/?f=s%3Ds_2-s_3%5C%5C%20%281.00%20m%29%3D8gt%5E2-4.5gt%5E2%3D3.5gt%5E2%5C%5C%20t%5E2%3D%5Cfrac%7B1.00%20m%7D%7B%283.5%29%289.8m%2Fs%5E2%29%7D%20%3D0.02915s%5E2)
The first drop is at the bottom and it takes 5t seconds to reach down.
The height of the roof h is the distance traveled by the first drop and is given by,
![h=\frac{1}{2} g(5t)^2=\frac{25t^2}{2g} =\frac{25(0.02915s^2)}{2(9.8m/s^2)} =3.57 m](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B1%7D%7B2%7D%20g%285t%29%5E2%3D%5Cfrac%7B25t%5E2%7D%7B2g%7D%20%3D%5Cfrac%7B25%280.02915s%5E2%29%7D%7B2%289.8m%2Fs%5E2%29%7D%20%3D3.57%20m)
the height of the roof is 3.57 m
Answer:
259 Hz or 269 Hz
Explanation:
Beat: This is the phenomenon obtained when two notes of nearly equal frequency are sounded together. The S.I unit of beat is Hertz (Hz).
From the question,
Beat = f₂-f₁................ Equation 1
Note: The frequency of the other instrument is either f₁ or f₂.
If the unknown instrument's frequency is f₁,
Then,
f₁ = f₂-beat............ equation 2
Given: f₂ = 264 Hz, Beat = 5 Hz
Substitute into equation 2
f₁ = 264-5
f₁ = 259 Hz.
But if the unknown frequency is f₂,
Then,
f₂ = f₁+Beat................. Equation 3
f₂ = 264+5
f₂ = 269 Hz.
Hence the beat could be 259 Hz or 269 Hz