Answer:
The maximum distance traveled is 4.73 meters in 0.23 seconds.
Step-by-step explanation:
We have that the distance traveled with respect to time is given by the function,
.
Now, differentiating this function with respect to time 't', we get,
d'(t)=9.8t-2.3
Equating d'(t) by 0 gives,
9.8t - 2.3 = 0
i.e. 9.8t = 2.3
i.e. t = 0.23 seconds
Substitute this value in d'(t) gives,
d'(t) = 9.8 × 0.23 - 2.3
d'(t) = 2.254 - 2.3
d'(t) = -0.046.
As, d'(t) < 0, we get that the function has the maximum value at t = 0.23 seconds.
Thus, the maximum distance the skateboard can travel is given by,
.
i.e.
.
i.e.
.
i.e.
.
i.e. d(t) = 4.73021
Hence, the maximum distance traveled is 4.73 meters in 0.23 seconds.
Answer:
x = -7
Step-by-step explanation:
−30=5(x+1)
Divide each side by 5
-30/5=5/5(x+1)
-6 =x+1
Subtract 1 from each side
-6-1 = x+1-1
-7 =x
6.75 is the absolute value of 6.75 absolute value is distance from zero and 6.75 is 6.75 from 0 so is -6.75
Plug x and y when you type in the calculator
2-2(2+3) and see your answer
Answer:
answer for this question is 6