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cricket20 [7]
3 years ago
15

Please help! Will give brainliest. 10 points. Show work!

Physics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

421.83 m.

Explanation:

The following data were obtained from the question:

Height (h) = 396.9 m

Initial velocity (u) = 46.87 m/s

Horizontal distance (s) =...?

First, we shall determine the time taken for the ball to get to the ground.

This can be calculated by doing the following:

t = √(2h/g)

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 396.9 m

Time (t) =.?

t = √(2h/g)

t = √(2 x 396.9 / 9.8)

t = √81

t = 9 secs.

Therefore, it took 9 secs fir the ball to get to the ground.

Finally, we shall determine the horizontal distance travelled by the ball as illustrated below:

Time (t) = 9 secs.

Initial velocity (u) = 46.87 m/s

Horizontal distance (s) =...?

s = ut

s = 46.87 x 9

s = 421.83 m

Therefore, the horizontal distance travelled by the ball is 421.83 m

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A car initially traveling at 27.2 m/s undergoes a constant negative acceleration of magnitude 1.90 m/s2 after its brakes are app
zubka84 [21]

Answer:

Therefore, the revolutions that each tire makes is:

\Delta \theta=22\: rev

Explanation:

We can use the following equation:

\omega_{f}^{2}=\omega_{i}^{2}-2\alpha \Delta \theta (1)

The angular acceleration is:

a_{tan}=\alpha R

\alpha=\frac{1.9}{0.325}

\alpha=5.85\: rad/s^{2}

and the initial angular velocity is:

\omega_{i}=\frac{v}{R}

\omega_{i}=\frac{27.2}{0.325}

\omega_{i}=83.69\: rad/s

Now, using equation (1) we can find the revolutions of the tire.

0=83.69^{2}-2*25.85 \Delta \theta

\Delta \theta=135.47\: rad

Therefore, the revolutions that each tire makes is:

\Delta \theta=22\: rev

I hope it helps you!

6 0
3 years ago
r was thirsty and decided to mix up a pitcher of lemonade. She put lemon juice, water, and sugar into a pitcher and stirred it t
slamgirl [31]
She could tell by how many components she put in. The compounds, are like the ingredients. The Mixture is all the ingredients stirred together.
7 0
3 years ago
Read 2 more answers
Fe₂O3<br> + co<br> →<br> Fe3O4 + CO₂
Goryan [66]

Explanation:

                    Fe₂O₃  + CO  → Fe₃O₄ + CO₂

Balancing the equation above, we can derive simple mathematical equations that are very easy to solve.

             aFe₂O₃  + bCO  → cFe₃O₄ + dCO₂

a,b,c and d are the coefficients needed to balance the equation above;

  Conserving Fe; 2a = 3c

                       O: 3a + b = 4c + 2d

                        C: b = d

 let a = 1;

      c = \frac{2}{3}

      Since b = d

                  3a + d = 4c + 2d

                    3a = 4c + 2d - d

                     3a = 4c + d

           a = 1, c = \frac{2}{3}

                    3 = 4 x \frac{2}{3}  +  d

                   d = \frac{1}{3}

                    b = \frac{1}{3}

multiplying a, b, c and d by 3:

            a = 3    b = 1     c = 2   and d = 1

                  3Fe₂O₃  + CO  → 2Fe₃O₄ + CO₂

Learn more:

Balanced equation brainly.com/question/2612756

#learnwithBrainly

6 0
3 years ago
A long, straight metal rod has a radius of 5.75 cm and a charge per unit length of 33.3 nC/m. Find the electric field at the fol
PIT_PIT [208]

Answer:

Explanation:

From the question;

We will make assumptions of certain values since they are not given but the process to achieve the end result will be the same thing.

We are to calculate the following task, i.e. to determine the electric field at the distances:

a)  at 4.75 cm

b)  at 20.5 cm

c) at 125.0 cm

Given that:

the charge (q) = 33.3 nC/m

= 33.3 × 10⁻⁹ c/m

radius of rod = 5.75 cm

a) from the given information, we will realize that the distance lies inside the rod. Provided that there is no charge distribution inside the rod.

Then, the electric field will be zero.

b) The electric field formula E = \dfrac{kq }{d}

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{0.205}

E = 1461.95 N/C

c) The electric field E is calculated as:

E = \dfrac{9 \times 10^9 \times (33.3 \times 10^{-9}) }{1.25}

E = 239.76 N/C

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Which best describes electromagnetic waves moving from gamma rays to radio waves along the electromagnetic spectrum
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Answer:

Explanation:

No

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