Answer:
Mass will be same on moon as on Earth but weight will be one-sixth of Earth.
Explanation:
Mass of a body doesn't depend on gravity. Mass is a constant quantity. So, mass on moon will be same as mass on Earth.
But, the weight of a body depends on gravity as weight is given as:
Therefore, if 
is acceleration due to gravity on Earth, then weight on Earth is, 
Now, gravity on moon is one-sixth of Earth. So, 
Therefore, weight of the body on moon is, 
Therefore, a body has same mass both on moon and Earth but weight on moon is one-sixth of the weight on Earth.
Explanation:
In physics, work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement. A force is said to do positive work if (when applied) it has a component in the direction of the displacement of the point of application. A force does negative work if it has a component opposite to the direction of the displacement at the point of application of the force.
Quick Facts: Common symbols, SI unit ...
Work
A baseball pitcher does positive work on the ball by applying a force to it over the distance it moves while in his grip.
Common symbols
W
SI unit
joule (J)
Other units
Foot-pound, Erg
In SI base units
1 kg⋅m2⋅s−2
Derivations from
other quantities
W = F ⋅ s
W = τ θ
Dimension
M L2 T−2
Close
For example, when a ball is held above the ground and then dropped, the work done by the gravitational force on the ball as it falls is equal to the weight of the ball (a force) multiplied by the distance to the ground (a displacement). When the force F is constant and the angle between the force and the displacement s is θ, then the work done is given by:
{\displaystyle W=Fs\cos {\theta }}{\displaystyle W=Fs\cos {\theta }}
Work is a scalar quantity, so it has only magnitude and no direction. Work transfers energy from one place to another, or one form to another. The SI unit of work is the joule (J), the same unit as for energy.
Answer:
The speed of the object is (
)m/s
The magnitude of the acceleration is 4.00m/s²
Explanation:
Given - position vector;
r = (2.0 + 3.00t)i + (3.0 - 2.00t²)j -------------------(i)
To get the speed vector (
), take the first derivative of equation (i) with respect to time t as follows;
= 
= ![\frac{d[(2.0 + 3.00t)i + (3.0 - 2.00t^2)j] }{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5B%282.0%20%2B%203.00t%29i%20%2B%20%283.0%20-%202.00t%5E2%29j%5D%20%20%7D%7Bdt%7D)
= ------------------------(ii)
To get the acceleration vector (
), take the first derivative of the speed vector in equation(ii) as follows;
j
The magnitude of the acceleration |a| is therefore given by
|a| = |-4.00|
|a| = 4.00 m/s²
In conclusion;
the speed of the object is ()m/s
the magnitude of the acceleration is 4.00m/s²
Inertia is that quantity which depends solely upon mass. The more mass, the more inertia. Momentum is another quantity in Physics which depends on both mass and speed.
Answer:
The weight of the wheelbarrow and the road is 784 N and the force required to lift the wheelbarrow is 784 N.
Explanation:
Given that,
The total mass of the wheelbarrow and the road is 80 kg.
The weight of an object is given by :
W = mg
where
g is acceleration due to gravity
So,
W = 80 × 9.8
= 784 N
So, the force required to lift the wheelbarrow is equal to its weight i.e. 784 N.
