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Sindrei [870]
3 years ago
11

Pls help I will give Brainliest to First and Correct Answer.

Physics
1 answer:
postnew [5]3 years ago
4 0

Answer:

I would say pushing it from the top because when you push anything from the top it basically flips over. You can go ahead and try to push anything forward from the top and starts tipping forward. I think the reason would be because you're putting weight only on the top of the tv and that is what would cause it to topple

Explanation: Hope this helps:)

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What mechanical layer lies below the lithosphere
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The <span>asthenosphere is under the lithosphere.</span>
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Assume you have a rocket in Earth orbit and want to go to Mars. The required change in velocity is ΔV≈9.6km/s . There are two op
Nostrana [21]

Answer: Part 1: Propellant Fraction (MR) = 8.76

Part 2: Propellant Fraction (MR) = 1.63

Explanation: The Ideal Rocket Equation is given by:

Δv = v_{ex}.ln(\frac{m_{f}}{m_{e}} )

Where:

v_{ex} is relationship between exhaust velocity and specific impulse

\frac{m_{f}}{m_{e}} is the porpellant fraction, also written as MR.

The relationship v_{ex} is: v_{ex} = g_{0}.Isp

To determine the fraction:

Δv = v_{ex}.ln(\frac{m_{f}}{m_{e}} )

ln(MR) = \frac{v}{v_{ex}}

Knowing that change in velocity is Δv = 9.6km/s and g_{0} = 9.81m/s²

<u>Note:</u> Velocity and gravity have different measures, so to cancel them out, transform km in m by multiplying velocity by 10³.

<u />

<u>Part 1</u>: Isp = 450s

ln(MR) = \frac{v}{v_{ex}}

ln(MR) = \frac{9.6.10^{3}}{9.81.450}

ln (MR) = 2.17

MR = e^{2.17}

MR = 8.76

<u>Part 2:</u> Isp = 2000s

ln(MR) = \frac{v}{v_{ex}}

ln (MR) = \frac{9.6.10^{3}}{9.81.2.10^{3}}

ln (MR) = 0.49

MR = e^{0.49}

MR = 1.63

8 0
3 years ago
Regions around the nucleus where electrons are most likely to be found are called
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Answer:

orbitals

Explanation:

The region where an electron is most likely to be is called an orbital. Each orbital can have at most two electrons. Some orbitals, called S orbitals, are shaped like spheres, with the nucleus in the center.

3 0
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A spherical snowball is melting in such a way that its radius is decreasing at a rate of 0.1 cm/min. At what rate is the volume
Ne4ueva [31]

Answer: 80.384 cubic cm /min

Explanation:

Let V denote the volume and r denotes the radius of the spherical snowball .

Given : \dfrac{dr}{dt}=-0.1\text{cm/min}

We know that the volume of a sphere is given by :-

V=\dfrac{4}{3}\pi r^3

Differentiating on the both sides w.r.t. t (time) ,w e get

\dfrac{dV}{dt}=\dfrac{4}{3}\pi(3r^2)\dfrac{dr}{dt}\\\\\Rightarrow\ \dfrac{dV}{dt}=4\pi r^2 (-0.1)=-0.4\pi r^2

When r= 8 cm

\dfrac{dV}{dt}=-0.4(3.14)(8)^2=-80.384

Hence, the volume of the snowball decreasing at the rate of 80.384 cubic cm /min.

6 0
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NEED Answer asap plz!!
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Answer:

I think a is the right not clear but

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