Answer:
Explanation:
Find the final velocity at which it struck the ground by using the kinetic energy formula.
Now use kinematics to solve for the vertical displacement. We were given the initial velocity and acceleration can be assumed to be 9.8
Δy = 13.6 meters
Answer:
<em>The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.</em>
Explanation:
<u>Mechanical Force</u>
The second Newton's law states the net force exerted by an external agent on an object of mass m is:
Where is the acceleration of the object. Note both the force and the acceleration are vectors. The relationship between them is the mass, a scalar.
This means the net force and the acceleration have the same direction.
The sailboat has a mass m= 350 Kg and moves at a=0.62 m/s^2. The magnitude of the net force acting on the boat is:
As stated above its direction is the same as the acceleration, thus:
The net force that acts on the sailboat has a magnitude of 217 N and is applied at an angle of 64° north of east.
They start at 1 meter and after 10 seconds they've moved to 6 meters.
6 - 1 = 5 meters
Complete question is;
The place you get your hair cut has two nearly parallel mirrors 6.50 m apart. As you sit in the chair, your head is 3.00 m from the nearer mirror. Looking toward this mirror, you first see your face and then, farther away, the back of your head. (The mirrors need to be slightly nonparallel for you to be able to see the back of your head, but you can treat them as parallel in this problem.) How far away does the back of your head appear to be?
Answer:
13 m
Explanation:
We are given;
Distance between two nearly parallel mirrors; d = 6.5 m
Distance between the face and the nearer mirror; x = 3 m
Thus, the distance between the back-head and the mirror = 6.5 - 3 = 3.5m
Now, From the given values above and using the law of reflection, we can find the distance of the first reflection of the back of the head of the person in the rear mirror.
Thus;
Distance of the first reflection of the back of the head in the rear mirror from the object head is;
y' = 2y
y' = 2 × 3.5
y' = 7
The total distance of this image from the front mirror would be calculated as;
z = y' + x
z = 7 + 3
z = 10
Finally, the second reflection of this image will be 10 meters inside in the front mirror.
Thus, the total distance of the image of the back of the head in the front mirror from the person will be:
T.D = x + z
T.D = 3 + 10
T.D = 13m