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vivado [14]
2 years ago
8

Given the following balanced equation:

Chemistry
1 answer:
svetlana [45]2 years ago
3 0
So you would just take the coefficient and put it into ratio form

Answers:
1) 4:5
2)4:6
3)6:4
4)6:6
5)6:4
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Silver nitrate solution reacts with calcium chloride solution according to the equation: 2 AgNO3 + CaCl2 → Ca(NO3)2 + 2 AgCl All
HACTEHA [7]

Answer:

14.33 g

Explanation:

Solve this problem based on the stoichiometry of the reaction.

To do that we need the molecular weight of the masses involved and then calculate the number of moles, find the limiting reagent and  finally calculate the mass of AgCl.

                      2 AgNO₃   + CaCl₂    ⇒   Ca(NO₃)₂   + 2 AgCl

mass, g                  6.97        6.39                                     ?

MW ,g/mol         169.87      110.98                                  143.32

mol =m/MW           0.10         0.06                                    0.10

From the table above AgNO₃ is the limiting reagent and we will produce 0.10 mol AgCl which is a mass :

0.10 mol x 143.32 g/mol = 14.33 g

5 0
4 years ago
Cience, Life Science
Rudiy27

Answer:

I think the answer is All of these answers are correct.

4 0
3 years ago
A solution is made by mixing of water and of acetic acid . Calculate the mole fraction of water in this solution. Be sure your a
Molodets [167]

Answer:

The answer is "0.35".

Explanation:

please find the complete question in the attached file.

Mass of CH_3C0_2 H= 77 \ g \\\\

Molar mass of CH_3C0_2 H = 60.05 \  \frac{g}{mol} \\\\

No of moles in n_{CH_3CO_2H} = 77 \ g \times  \frac{1 \ mol \ CH_3C0_2H}{60.05 \ g}  

                                          = 1.28 \ mol \ CH_3CO_2H

Mass of water (H_2O)= 42 \ g

The molar mass of water (H_2O)= 18.02 \  \frac{g}{mol}

moles of water n_{H_2O}:

= 42 \ g \times \frac{1 mol H_2O}{18.02 \ g} \\\\= 2.33 \ mol \ H_2 O

Molfraction of acetic acid:

X CH_2CO_2H = \frac{n_{CH_3CO_2H}}{n_CH_3CO_2H +n_{H_2}}\\\\

                     =\frac{1.28 \ mol}{1.28 \ mo1 + 2.33 mol}\\\\ = 0.354\\\\= 0.35

7 0
3 years ago
3. Why didn't other scientist claim that there was an irwisible crystal layer around the Moon become widely accepted?
Oksana_A [137]
What is most widely accepted today is the giant-impact theory. It the Moon formed during a collision between the Earth and another small planet, about the There may indeed be several objects in orbit around Earth.
6 0
3 years ago
Help please thank u !!
MAXImum [283]
2nd law i think

Have a good evening and im sorry if im wrong

Bai sisters
3 0
3 years ago
Read 2 more answers
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