To balance a reaction, we must say to it that the number of elements in one side is equal to the other side. For a combustion reaction such as the one given, we first need to balance the number of carbon atoms, then the hydrogen atoms and lastly the oxygen atoms.
<span>C4H10 + 13/2O2 → 4CO2 + 5H2O.</span>
Combustion
Explanation:
This reaction is called a combustion reaction. It is very peculiar to reactions involving hydrocarbons.
In such reactants, oxygen gas is used as a reactant. It combines with fuel usually the hydrocarbon to produce heat and light energy.
For the combustion of most hydrocarbons, water and carbon dioxides are usually the product.
2CH₂ + 3O₂ → 2CO₂ + 2 H₂O
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Answer:
atomic structure - The nucleus is at the center of an atom, where most of the charge and mass are concentrated
protons - a stable subatomic particle occurring in all atomic nuclei, with a positive electric charge equal in magnitude to that of an electron, but of opposite sign.
neutrons - a subatomic particle of about the same mass as a proton but without an electric charge, present in all atomic nuclei except those of ordinary hydrogen.
electrons - a stable subatomic particle with a charge of negative electricity, found in all atoms and acting as the primary carrier of electricity in solids.
atom vs. ion - an atom is the basic unit of a chemical element, and an ion is an atom or molecule with a net electric charge due to the loss or gain of one or more electrons. See also cation, anion.
Mass number - total number of protons, and neutrons in an atom.
Explanation:
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Answer:

Explanation:
To convert form grams to moles, the molar mass must be used. This is the mass (in grams) in 1 mole of a substance.
We can use the values on the Periodic Table. First, find the molar masses of the individual elements: carbon and oxygen.
- C: 12.011 g/mol
- O: 15.999 g/mol
Check for subscripts. The subscript of 2 after O means there are 2 oxygen atoms, so we have to multiply oxygen's molar mass by 2 before adding.
- O₂: 2* (15.999 g/mol)=31.998 g/mol
- CO₂: 12.011 g/mol + 31.998 g/mol =40.009 g/mol
Use the molar mass as a ratio.

Multiply by the given number of grams.

Flip the fraction so the grams of carbon dioxide cancel.



The original measurement of grams has 2 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.
The ten thousandth place has a 5, so we round the 4 to a 5.

2.4 grams of carbon dioxide is about 0.055 moles.