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kobusy [5.1K]
2 years ago
14

Consider the following intermediate chemical equations. 2 equations. First: upper C (s) plus one half upper O subscript 2 (g) ri

ght arrow upper C upper O (g). Second: upper C upper O (g) plus one half upper O subscript 2 (g) right arrow upper C upper O subscript 2 (g). How will oxygen appear in the final chemical equation? Upper O subscript 2 (g). As a product Upper O subscript 2 (g). As a reactant O(g) as a product 2O(g) as a reactant.
Chemistry
2 answers:
Salsk061 [2.6K]2 years ago
4 0

Answer:

34.2

Explanation:

Bc it is the loser one to it

Dmitrij [34]2 years ago
3 0

The oxygen in the final equation appears as reactant Upper O subscript 2 (g). Thus, option A is correct.

The chemical equations are the representation of the chemical formula involved in the equation as the reactant and the formed product.

<h3>What will be the form of oxygen?</h3>

The given chemical equations are:

  1. \rm C\;(s)\;+\;\frac{1}{2}\;O_2\;(g)\rightarrow\;CO\;(g)
  2. \rm CO\;(g)+\;\frac{1}{2}\;O_2\;(g)\rightarrow\;CO_2\;(g)

The final chemical equation formed for the formation of Carbon dioxide is the sum of the two equations.

The final equation is achieved by substituting equation 1 in equation 2.

\rm C\;(s)\;+\;\frac{1}{2}\;O_2\;(g)\;+\;\dfrac{1}{2}\;O_2\;(g)\;\rightarrow\;CO_2\;(g)\\\\   C\;(s)\;+\;O_2\;(g)\;\rightarrow\;CO_2\;(g)

The oxygen in the final equation appears as reactant Upper O subscript 2 (g). Thus, option A is correct.

Learn more about the final equation, here:

brainly.com/question/2264209

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