1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
WITCHER [35]
2 years ago
9

The enthalpy of combustion for octane (C8H18(l)), a key component of gasoline, is -5,074 kJ/mol. This value is the Delta. Hrxn f

or which of the following reactions? 2C8H18(l) 25O2(g) Right arrow. 16CO2(g) 18H2O(g) C8H18(l) 12. 5O2(g) Right arrow. 8CO2(g) 9H2O(g) 16CO2(g) 18H2O(g) Right arrow. 2C8H18(l) 25O2(g) 8CO2(g) 9H2O(g) Right arrow. C8H18(l) 12. 5O2(g).
Chemistry
1 answer:
Inessa [10]2 years ago
6 0

Combustion can be defined as the reaction of a compound with oxygen. The enthalpy of combustion of octane is \Delta H_{\rm rxn} for \rm C_8H_{18}\;+\;25\;O_2\;\rightarrow 8\;CO_2\;+\;9\;H_2O.

<h3>What is the enthalpy of reaction?</h3>

The enthalpy of reaction is the amount of heat energy absorbed or lost by the molecules in the chemical reaction.

The enthalpy of combustion is the amount of heat energy released by the compound in the reaction with oxygen.

The reaction in which heat is liberated with the reaction of a compound with oxygen has an enthalpy of combustion, equivalent to the enthalpy of reaction.

The combustion of octane can be given as:

\rm C_8H_{18}\;+\;25\;O_2\;\rightarrow 8\;CO_2\;+\;9\;H_2O

Thus, the reaction has combustion energy equivalent to the enthalpy of the reaction is \rm C_8H_{18}\;+\;25\;O_2\;\rightarrow 8\;CO_2\;+\;9\;H_2O. Thus, option B is correct.

Learn more about enthalpy of reaction, here:

brainly.com/question/1657608

You might be interested in
i need help im a dum bleep who kept talking to guys on dc and one wont leave me alone what do i do (▰˘◡˘▰) (i already blocked hi
Andrew [12]

Answer:

Delete your discord acc, and make another one. Prob should change email tbh. If he keeps doing it you can report him, because it's like online stalking.

Explanation:

6 0
3 years ago
Which inquiry skill is based on identifying common features?
expeople1 [14]
<span>Classify is the answer hope this helps :)</span>
3 0
3 years ago
Which of the following statements is accurate
Rufina [12.5K]
A. If an objects velocity is decreasing, the object is said to be decelerating not accelerating.
B. If an objects velocity changes, it is either experiencing acceleration or deceleration 
C. If an object is said to be decelerating, its velocity must be decreasing.
D. If an objects velocity remains constant, its acceleration is zero. 

∴ B is correct
3 0
3 years ago
Read 2 more answers
What is the difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm
Zanzabum

Answer:

The difference in mass between 3.01×10^24 atoms of gold and a gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm is :

<u>Difference</u>  <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

Explanation:

<u>Part I :</u>

n =\frac{3.01\times 10^{24}}{6.022\times 10^{23}}

n = 4.9983

n = 4.99 moles

(Note : You can also take n = 5 mole )

Molar mass of gold = 196.96 g/mole

This means, 1 mole of gold(Au) contain = 196.96 grams

So, 4.99 moles of gold contain = 5\times 196.96 g

4.99 moles of gold contain = 984.8 g

Mass of {3.01\times 10^{24}} atoms of gold = 984.5 g

<u>Part II :</u>

Density of Gold = 19.32 g/cm^{3}

Volume of the cuboid = length\times breadth\times height

Volume of the gold bar =6.00\times 4.25\times 2.00

Volume of the gold bar = 51cm^{3}

Using formula,

Density = \frac{mass}{Volume}

Mass = Density\times Volume

Mass = 19.32 \times 51

Mass = 985.32 g

So, A  gold bar with the dimensions 6.00 cm X 4.25 cm X 2.00 cm has mass of <u>985.32 g</u>

<u>Difference</u>  <u>in mass</u> =<u> 985.32 - 984.5 = 0.82 g</u>

3 0
3 years ago
Using the Rydberg formula, calculate the initial energy level when an electron in a hydrogen atom transitions into n= 2 and emit
EleoNora [17]

Answer:

1

Explanation:

Using the Rydberg formula as:

\frac {1}{\lambda}=R_H\times Z^2\times (\frac {1}{n_{1}^2}-\frac {1}{n_{2}^2})

where,

λ is wavelength of photon

R = Rydberg's constant (1.097 × 10⁷ m⁻¹)

Z = atomic number of atom

n₁ is the initial final level and n₂ is the final energy level

For Hydrogen atom, Z= 1

n₂ = 2

Wavelength = 410.1 nm

Also,

1 nm = 10⁻⁹ m

So,

Wavelength = 410.1 × 10⁻⁹ m

Applying in the formula as:

\frac {1}{410.1\times 10^{-9}}=1.097\times 10^7\times 1^2\times (\frac {1}{n_{1}^2}-\frac {1}{2^2})

Solving for n₁ , we get

n₁ ≅ 1

3 0
3 years ago
Read 2 more answers
Other questions:
  • What process uses analysis of the decay of atomic particles to determine exact age?
    10·2 answers
  • Natural gas is a A. type of solar energy. B. type of electricity. C. nonrenewable resource. D. renewable resource.
    12·1 answer
  • How many grams of CaCl2 should be dissolved in 633.1 mL of water to make a 0.35 M solution of CaCl2?
    12·1 answer
  • L
    10·1 answer
  • 4. Do the arrows you drew on Figure B represent an action force or a reaction force!
    6·1 answer
  • Formula for calcium hydroxide
    7·2 answers
  • A sample of nitrogen gas is in a 65.0-L automobile air bag and has a pressure of 745 mm Hg. What is the pressure of this sample
    8·1 answer
  • I need help with this question
    14·1 answer
  • How many Al atoms are there in 40.5 g of Al foil? Al:27
    7·1 answer
  • Which of the following liquids has the highest viscosity
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!