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GREYUIT [131]
3 years ago
15

Help please I really need it. :(

Chemistry
1 answer:
stich3 [128]3 years ago
7 0

Answer:

the second answer

Explanation:

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If each NADHNADH generates 3 ATPATP molecules and each FADH2FADH2 generates 2 ATPATP molecules, calculate the number of ATPATP m
Nadusha1986 [10]

Answer:

128~ATP

Explanation:

The metabolic pathway by which energy can be obtained from a fatty acid is called <u>"beta-oxidation"</u>. In this route, acetyl-Coa is produced by removing <u>2 carbons</u> from the fatty acid for each acetyl-Coa produced. In other words, for each round, 1 acetyl Coa is produced and for each round 2 carbons are removed from the initial fatty acid. Therefore, the first step is to calculate the <u>number of rounds</u> that will take place for an <u>18-carbon fatty</u> acid using the following equation:

Number~of~Rounds=\frac{n}{2}-1

Where "n" is the <u>number of carbons</u>, in this case "18", so:

Number~of~Rounds=\frac{18}{2}-1~=~8

We also have to calculate the amount of Acetyl-Coa produced:

Number~of~Acetyl-Coa=\frac{18}{2}~=~9

Now, we have to keep in mind that in each round in the beta-oxidation we will have the <u>production of 1 FADH_2 and 1 NADH</u>. So, if we have 8 rounds we will have 8 FADH_2 and 8 NADH.

Finally, for the total calculation of ATP. We have to remember the <u>yield for each compound</u>:

-) 1~FADH_2~=~2~ATP

-) 1~NADH~=~3~ATP

-) Acetyl~CoA~=~10~ATP

Now we can do the total calculation:

(8*2)~+~(8*3)~+~(9*10)=130~ATP

We have to <u>subtract</u>  "2 ATP" molecules that correspond to the <u>activation</u> of the fatty acid, so:

130-2=128~ATP

In total, we will have 128 ATP.

I hope it helps!

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3 years ago
Name one gas that can form when the carbon in coal burns! And describe its harmful effects
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9A. A sample of hydrogen at 1.56 atm had it's pressure decreased to 0.73
densk [106]

Answer:

351.43mL

Explanation:

To calculate the original volume of hydrogen gas in this question, the Boyle's law equation will be used. Boyle's law equation is:

P1V1 = P2V2

Where; P1 = initial pressure

V1 = initial volume

P2 = final pressure

V2 = final volume

According to this question, the P1= 1.56atm, V1 = ?, P2 = 0.73atm, V2 = 751mL

Hence;

P1V1 = P2V2

1.56 × V1 = 0.73 × 751

1.56 V1 = 548.23

V1 = 548.23/1.56

V1 = 351.43mL

Therefore, the original volume of hydrogen gas is 351.43 mL.

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Explanation:

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