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Alisiya [41]
3 years ago
11

Describe the profile you would expect for a biological catalyst. Complete the sentences to explain why an enzyme is different th

an an inorganic catalyst. Match the words to the appropriate blanks in the sentences.
Multiple
Organic
slower
a single
high
faster
inroganic
low
about the same

When looking at the plot G versus reaction coordinate, the profile for a biological catalyst (e.g. an enzyme) will have __________ transition state(s), with an overall activation energy that is __________ in comparison to the uncatalyzed reaction.

Enzymes have a __________ molecular weight and are __________ compounds, while inorganic catalysts often have a __________ molecular weight and are __________ compounds.

When comparing rates, enzymes are typically several times __________ than inorganic catalysts.
Chemistry
1 answer:
uysha [10]3 years ago
5 0

Answer:

- When looking at the plot G versus reaction coordinate, the profile for a biological catalyst (e.g. an enzyme) will have <u>about the same</u> transition state(s), with an overall activation energy that is <u>low </u>in comparison to the uncatalyzed reaction.

- Enzymes have a <u>high </u>molecular weight and are <u>organic</u> compounds, while inorganic catalysts often have a <u>low</u> molecular weight and are <u>inorganic</u> compounds.

- When comparing rates, enzymes are typically several times <u>faster</u> than inorganic catalysts.

Explanation:

Enzymes are organic molecules capable of producing a faster chemical reaction. In an enzymatic reaction the transition state -corresponding to the state in which the substrates or products are equally likely- tends to be the same, while the energy required for the reaction decreases.

The differences between an enzyme and an inorganic catalyst are structural and functional:

  • <em>Enzymes are organic and of high molecular weight and catalysts are inorganic and of low molecular weight. </em>
  • <em>An enzyme can change its structure during a reaction, while the configuration of a catalyst is the same. </em>
  • <em>The reaction catalyzed by an enzyme is about 10⁶ to 10¹² times faster than with a catalyst.</em>
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A sample of 14.5 g of sodium bicarbonate (NaHCO3) was dissolved in 100 ml of water in a coffee-cup calorimeter with no lid by th
Ann [662]

Answer:

The ΔH of the reaction is + 12.45 KJ/mol

Explanation:

Mass of water= 100ml = 100g. (You should always assume 1cm3 of water as 1g)

heat capacity of water = 4.18 Jk-1 Mol-1

Change in temperature = (19.86 - 25.00) = -5.14 K (This is an endothermic reaction because of the fall in temperature)

Molar mass of NaHCO3 = 84 g/mol

Mole of NaHCO3 = 14.5 / 84 = 0.173 mol

Step 1 : Calculate the heat energy (Q) lost by the water.

            Q = M x C x ΔT

            Q = -100 x 4.18 x (-5.14)

            Q = 2148.5 joules

            Q = 2.1485 K J

Step 2: Calculating the ΔH of the reaction?

          ΔH = Q / number of moles of NaHCO3

          ΔH = 2.1485 / 0.173

          ΔH = 12.42 KJ/mol

3 0
3 years ago
1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium
lilavasa [31]

Answer:

This question is incomplete, here's the complete question:

1. Calculate the concentration of hydronium ion of both buffer solutions at their starting pHs. Calculate the moles of hydronium ion present in 20.0 mL of each buffer.

Buffer A

Mass of sodium acetate used: 0.3730 g

Actual ph of the buffer 5.27

volume of the buffer used in buffer capacity titration 20.0 mL

Concentration of standardized NaOH 0.100M

moles of Naoh needed to change the ph by 1 unit for the buffer 0.00095mol

the buffer capacity 0.0475 M

Buffer B

Mass of sodium acetate used 1.12 g

Actual pH of the buffer 5.34

Volume of the buffer used in buffer capacity titration 20.0 mL

Concentration if standardized NaOH 0.100 M

moles of Naoh needed to change the ph by 1 unit 0.0019 mol

the buffer capacity 0.095 M

2.) A change of pH by 1 unit means a change in hydronium ion concentration by a factor of 10. Calculate the number of moles of NaOH that would theoretically be needed to decrease the moles of hydronium you calculated in #1 by a factor of 10 for each buffer. Are there any differences between your experimental results and the theoretical calculation?

3.) which buffer had a higher buffer capacity? Why?

Explanation:

Formula,

moles = grams/molar mass

molarity = moles/L of solution

1. Buffer A

molarity of NaC2H3O2 = 0.3731 g/82.03 g/mol x 0.02 L = 0.23 M

molarity of HC2H3O2 = 0. 1 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.23/0.1)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

Buffer B

molarity of NaC2H3O2 = 1.12 g/82.03 g/mol x 0.02 L = 0.68 M

molarity of HC2H3O2 = 0.3 M

Initial pH

pH = pKa + log(base/acid)

= 4.74 + log(0.68/0.3)

= 5.10

pH = -log[H3O+]

[H3O+] = 7.91 x 10^-6 M

In 20 ml buffer,

moles of H3O+ = 7.91 x 10^-6 M x 0.02 L

= 1.58 x 10^-7 mol

2. let x moles of NaOH is added,

Buffer A,

pH = 5.10

[H3O+] = 7.91 x 10^-6 M

new pH = 4.10

new [H3O+] = 7.91 x 10^-5 M

moles of NaOH to be added = (7.91 x 10^-5 - 7.91 x 10^-6) x 0.02 L

= 1.42 x 10^-6 mol

3. Buffer B with greater concentration of NaC2H3O2 and HC2H3O2 has higher buffer capacity as it resists pH change to a wider range due to addition of acid or base to the system as compared to low concentration of Buffer A

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3 years ago
Mole ratios how can the coefficients in a chemical equation be interpreted
navik [9.2K]

Answer:

The coefficient in a balanced chemical equation  indicates the mole ratio of both reactants and products.  

Explanation:

For example lets consider the reation between Hydrogen and Oxygen to form water:

2H2 + O2 ----------------------- 2H2O

In this reaction, the coefficients of the balanced reaction can be transformed to Mole ratio according to Avogadro's Law which states that at standard temperature and pressure, equal volume of gases contain the same  number of moles.

So the mole ratio for the above equation is  the  ratio of the coefficient:

2moles     :     1 mole               :          2 moles

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3 years ago
What chemical process is used to convert oils into fats and semi solids
dem82 [27]
This process is called hydrogenation. It involves the conversion of oils that are liquid into semi-solid fats. Example products that makes use of this process is the margarine and shortenings. Hope this answers the question. Have a nice day.
6 0
3 years ago
The stability of an isotope is based on its
sattari [20]
Option 4. ratio of electrons to protons

Isotope that has atomic number of 82 is stable. An element that has an atomic number ∠82 more stable except Tc and Pm. Also there is the concept that isotopes consisting a combination of even-even,even-odd,odd-even, and odd-odd are all stable. Many isotopes with no magic numbers of nucleons are stable
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