Answer:
Got your back
Explanation:
If the ions derived from different atoms are isoelectronic species, then they all have same number of electrons in their electronic shells and will have got same electronic configuration but their nuclear charge will differ because of their difference in number of protons in the nucleus. With increase in number of protons in the nucleus the electrons are more attracted towards nucleus thereby causing the decrease in ionic radius. On this principle our problem will be solved
The given ions are
7N-3
→no. of proton
=7
and
no of electron
=10
8O-2
→
no. of proton
=8
and
no of electron
=10
9F-→
no. of proton=9
and no of electron=10
11Na→
no. of proton=11
and no of electron=10
12 Mg-3→
no. of proton=12 and
no of electron=10
Hence the increasing order of ionic radius is
12Mg-3<11Na+<9F-<8O-2<7N-3
To rmember ->For isoelectronic species lower the nuclear charge higher the radius
Answer:
The value of
for xylene is 4.309°C/m.
The molar mass of pentane using this data is 73.82 g/mol.
Explanation:

where,
=depression in freezing point
= freezing point constant
we have :
1) freezing point constant for xylene =
=?
Mass of toluene = 0.193 g
Mass of xylene = 2.532 kg = 0.002532 kg ( 1 g =0.001 kg)



The value of
for xylene is 4.309°C/m.
2)
Mass of pentane = 0.123 g
molar mass of pentame= M
Mass of xylene = 2.493 g = 0.002493 kg
Freezing point Constant of xylene = 

M = 73.82 g/mol
The molar mass of pentane using this data is 73.82 g/mol.
Answer:
has two double C-C bonds
Explanation:
A saturated compound is a compound having the full complement of hydrogen atoms for every carbon atom while an unsaturated compound does not contain the full complement of hydrogen atoms for every atom of carbon.
If we look at C3H4, the only possible structure of the compound is H2C=C=CH2. We can see from this arrangement that the compound contains a cumulative double bond. This is the specific structure that fits into one of the descriptions in the options, the compound contains two double bonds.
Answer:
Sn₃(PO₄)₄ - tin(IV) phosphate.
Explanation:
Hope it helps! :)
(1) Ploar covalent. is the answer.