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HACTEHA [7]
3 years ago
9

Which of the following phase changes only occurs in solids possessing vapor pressures above atmospheric pressure and at ambient

temperature?
a. Condensation
b. Melting
c. Sublimation
d. Deposition
Chemistry
1 answer:
GuDViN [60]3 years ago
4 0

<u>Answer:</u> The phase change process in which solids gets converted to gases is sublimation.

<u>Explanation:</u>

For the given options:

<u>Option a:</u>  Condensation

It is a type of process in which phase change occurs from gaseous state to liquid state at constant temperature.

Gas\rightleftharpoons Liquid

<u>Option b:</u>  Melting

It is a type of process in which phase change occurs from solid state to liquid state at constant temperature.

Solid\rightleftharpoons Liquid

<u>Option c:</u>  Sublimation

It is a type of process in which phase change occurs from solid state to gaseous state without passing through the liquid state at constant temperature.

Solid\rightleftharpoons Gas

<u>Option d:</u>  Deposition

It is a type of process in which phase change occurs from gaseous state to solid state without passing through the liquid state at constant temperature.

Gas\rightleftharpoons Solid

Hence, the phase change process in which solids gets converted to gases is sublimation.

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The K a of propanoic acid ( C 2 H 5 COOH ) is 1.34 × 10 − 5 . Calculate the pH of the solution and the concentrations of C 2 H 5
Zigmanuir [339]

Answer:

2.62.

Explanation:

Okay let us first write the parameters in the question in question above out. We are given the ka value of propanoic acid, C2H5COOH to be equals to 1.34 × 10^- 5. Also, we are given the value for the initial concentration of propanoic acid to be 0.441 M.

So, let us delve right into the solution to the question and we will be starting by writting the equation below;

C2H5COOH <--------> H^+ + C2H5COO^-.

Please note that this Reaction is a reversible Reaction.

Therefore, the basic things about acid is its great tendency to release Hydrogen ion in an aqeous solution.

So, we will be taken equation above and correspond it with the time and Concentration.

C2H5COOH <----> H^+ C2H5COO^-.

Initial concentration of the C2H5COOH = 0.441 M and the initial concentration of H^+ and C2H5COO^- are both zero.

So, after a time, t, concentration of C2H5COOH= 0.441 - x and at that time the concentration of H^+ and C2H5COO^- are both x and x respectively.

Hence, Ka = [C2H5COO^-] [H^+]/ C2H5COOH. -----------------------(**).

Therefore, slotting in the values from above into equation (**), we have;

1.34 × 10^-5 = [x] [x]/ [0.441 - x].

1.34 × 10^-5= x^2/ [0.441 - x].

x^2 = 1.34 × 10^-5(0.441) - 1.34 × 10^-5x.

x^2 + 1.34 × 10^-5x - 5.91× 10^-6.

x = 2.4×10^-3.

Hence, the concentration of the propanoic acid at time, t= 0.441 - 2.4 ×10^-3.

==> 0.44 M.

pH = -log [H^+].

Then, we have; pH= - log[2.4× 10^-3].

pH= 2.62.

4 0
3 years ago
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Colloids are solutions with particle size intermediate between true solutions and suspensions. Suspensions have large sized particles which settle when left undisturbed for sometime and thus can be filtered off easily. The particle size in colloids is less and hence they do not settle under the effect of gravity.

7 0
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The compound dinitrogen trioxide would have<br> the chemical formula?
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what is the name of the collection of elements on the right side of the periodic table with electrons sequentially filling orbit
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