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2 years ago

Aubrey has $ -24 in her bank account. A store credits her account with a $10 refund. How much does she now have in the bank?

Mathematics

1 answer:

xz_007 [3.2K]2 years ago

8 0

To get the answer you’ll need to add the $10 to the -24. After completing you’ll have the number -14. Glad to help :)

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Find the area of each circle. Use 3.14 for pi. 22m

PilotLPTM [1.2K]

Step-by-step explanation:

$area = {\pi}r^{2}$

A= 3.14 × 22^2

A = 1519.78 m^2

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3 years ago

True or False:

Deffense [45]

Answer: True

Step-by-step explanation:

It's True because graphing something like a symmetric on the x-axis then there can only be at least one x-intercept.

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3 years ago

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Answer:

d. 59.1 billion

Step-by-step explanation:

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3 years ago

Solve the system by using elementary row operations on the equations. Follow the systematic elimination procedure.

Natali5045456 [20]

Answer:

Step-by-step explanation:

The given equation is expressed as

x1 + 2x2 = -24- - - - - - - - --1

x1 + 7x2 = -11- - - - - - - --2

We would eliminate x1 by subtracting equation 2 from equation 1. It becomes

- 5x2 = - 13

Dividing both sides of the equation by - 5, it becomes

- 5x2/- 5 = - 13/- 5

x2 = 13/5

Substituting x2 = 13/5 into equation 2, it becomes

x1 + 7 × 13/5 = -11

x1 + 91/5 = - 11

x1 = - 11 - 91/5

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4 0

3 years ago

Identify a pattern in the given list of numbers. Then use this pattern to find the next number.

Rom4ik [11]

Answer:

The given sequence is geometric sequence

In the given pattern we have next number is $a_5=\frac{1}{4}$

Step-by-step explanation:

Given numbers are 64,-16,4,-1

To identify the pattern of the given numbers :

Let $a_1=64$ , $a_2=-16$ , $a_3=4$ and $a_4=-1$

To find the next number that is $a_5$

common ratio $r=\frac{a_2}{a_1}$

$=\frac{-16}{64}$

$r=-\frac{1}{4}$

$r=\frac{a_3}{a_2}$

$=\frac{4}{-16}$

$r=-\frac{1}{4}$

Therefore the common ration is $r=-\frac{1}{4}$

Therefore the given sequence is geometric sequence

The nth term of the geometric sequence is $a_n=a_1r^{n-1}$

Now find the 5th term so put n=5 , $a_1=64andr=\frac{-1}{4}$ we have

$a_5=64(\frac{-1}{4})^{5-1}$

$=64(\frac{-1}{4})^{4}$

$=64(\frac{1}{4})^{4}$

$=64(\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4})$

$=\frac{1}{4}$

Therefore $a_5=\frac{1}{4}$

8 0

3 years ago