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Bumek [7]
2 years ago
5

Aubrey has $ -24 in her bank account. A store credits her account with a $10 refund. How much does she now have in the bank?

Mathematics
1 answer:
xz_007 [3.2K]2 years ago
8 0
To get the answer you’ll need to add the $10 to the -24. After completing you’ll have the number -14. Glad to help :)
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P-&gt;q is false and p is true.<br> q is<br> a.true<br> b.false
kirill [66]

Answer:

Choice b. q has to be false.

Step-by-step explanation:

Consider the truth table of p \implies q (p implies q).

  • p is true and q is true: p \implies q would be true.
  • p is true and q is false: p \implies q would be false.
  • p is false and q is true: p \implies q would be true.
  • p is false and q is false: p \implies q would also be true.

The only combination where p \implies q is false is when p is true and q is false. Hence, the q\! here must be false.

3 0
3 years ago
Is B the answer??? PLEASE HELP
NARA [144]
Yes, you are correct!
6 0
3 years ago
Find the exact length of the curve. x=et+e−t, y=5−2t, 0≤t≤2 For a curve given by parametric equations x=f(t) and y=g(t), arc len
Rama09 [41]

The length of a curve <em>C</em> parameterized by a vector function <em>r</em><em>(t)</em> = <em>x(t)</em> i + <em>y(t)</em> j over an interval <em>a</em> ≤ <em>t</em> ≤ <em>b</em> is

\displaystyle\int_C\mathrm ds = \int_a^b \sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2} \,\mathrm dt

In this case, we have

<em>x(t)</em> = exp(<em>t</em> ) + exp(-<em>t</em> )   ==>   d<em>x</em>/d<em>t</em> = exp(<em>t</em> ) - exp(-<em>t</em> )

<em>y(t)</em> = 5 - 2<em>t</em>   ==>   d<em>y</em>/d<em>t</em> = -2

and [<em>a</em>, <em>b</em>] = [0, 2]. The length of the curve is then

\displaystyle\int_0^2 \sqrt{\left(e^t-e^{-t}\right)^2+(-2)^2} \,\mathrm dt = \int_0^2 \sqrt{e^{2t}-2+e^{-2t}+4}\,\mathrm dt

=\displaystyle\int_0^2 \sqrt{e^{2t}+2+e^{-2t}} \,\mathrm dt

=\displaystyle\int_0^2\sqrt{\left(e^t+e^{-t}\right)^2} \,\mathrm dt

=\displaystyle\int_0^2\left(e^t+e^{-t}\right)\,\mathrm dt

=\left(e^t-e^{-t}\right)\bigg|_0^2 = \left(e^2-e^{-2}\right)-\left(e^0-e^{-0}\right) = \boxed{e^2-\frac1{e^2}}

5 0
3 years ago
Solve 7x-9=28+4(x-1)
ANEK [815]
I got 10.333333333333
8 0
3 years ago
Part A: Factor 2x2c2 + 3xc2 − 35c2. Show your work. (4 points)
Debora [2.8K]

Answer:

a: 12

B: 5  

c: 15

Step-by-step explanation: because you have to multiply and divide but i might have the wrong answerr :((((


3 0
3 years ago
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