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3 years ago

The flow of electricity in a certain path is called.

Physics

1 answer:

JulijaS [17]3 years ago

5 0

The flow of electricity in a certain path is the circuit.

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An electron initially at rest, leaves a cathode and is uniformly accelerated in a

katrin [286]

Answer:

75 km/s^2

Explanation:

Divide the final velocity by the time needed to reach the final velocity.

(1500 m/s) /.02s = 75,000 m/s^2 = 75 km/s^2

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4 years ago

What is a substance that when mixed with water turns blue litmus paper red

alekssr [168]

When blue litmus paper is dipped in acid the paper turns red.

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5 0

4 years ago

Why is the cathode ray oscilloscope evacuated?

Stels [109]

Answer:

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Explanation:

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7 0

3 years ago

Do we know which has more potential energy? object A or B? Best answer with reasoning gets brainliest.

babymother [125]

Answer:

Object C has the most potential energy.

Between A and B, we do not know which has more potential energy.

Explanation:

We know the object with the most potential energy and this is the object at C.

Potential energy is the energy due to the position of a body above the ground surface.

The higher a body is above ground, the more its potential energy.

Potential energy = mass x acceleration due to gravity x height

So;

Object C has the most potential energy.

Between A and B, we do not know which has more potential energy.

This is because, the height and mass of the objects are not quantified using numbers.

Potential energy is a function of mass and height and acceleration due to gravity but acceleration due gravity is a constant.

3 0

3 years ago

A hot air balloon is on the ground, 200 feet from an observer. The pilot decides to ascend at 100 ft/min. How fast is the angle

liq [111]

Answer:

0.0031792338 rad/s

Explanation:

$\theta$ = Angle of elevation

y = Height of balloon

Using trigonometry

$tan\theta=y\dfrac{y}{200}\\\Rightarrow y=200tan\theta$

Differentiating with respect to t we get

$\dfrac{dy}{dt}=\dfrac{d}{dt}200tan\theta\\\Rightarrow \dfrac{dy}{dt}=200sec^2\theta\dfrac{d\theta}{dt}\\\Rightarrow 100=200sec^2\theta\dfrac{d\theta}{dt}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{100}{200sec^2\theta}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{1}{2}cos^2\theta$

Now, with the base at 200 ft and height at 2500 ft

The hypotenuse is

$h=\sqrt{200^2+2500^2}\\\Rightarrow h=2507.98\ ft$

Now y = 2500 ft

$cos\theta=\dfrac{200}{h}\\\Rightarrow cos\theta=\dfrac{200}{2507.98}=0.07974$

$\dfrac{d\theta}{dt}=\dfrac{1}{2}\times 0.07974^2\\\Rightarrow \dfrac{d\theta}{dt}=0.0031792338\ rad/s$

The angle is changing at 0.0031792338 rad/s

6 0

3 years ago