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Over [174]
4 years ago
6

the weight of an object on earth is 350 newtons. on mars the same object would weigh 134 newtons. what is the acceleration due t

o gravty on the surface of mars, given that it is 9.8 meters/second2 on earth?
Physics
1 answer:
Eddi Din [679]4 years ago
7 0
Mass will remain constant on both planet, let mass of the object be "m".
let x be the <span>acceleration due to gravity on the surface of mars.
Weight of object on earth = m *g , where g is </span><span>acceleration due to gravity on the surface of earth
</span>⇒350 =  m *  9.8
⇒m = 350  /  9.8                        .............................equation(1)
Weight of object on mars = m * x , where x is acceleration due to gravity on the surface of mars
134  =   m   *  x                           .............................equation(2)
putting the value of m from equation (1) in equation(2) , we get,
x     =   (134  *  9.8) / 350
⇒  x   =   3.572 m/s²
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Consider the first major feature (orderly motions). Which of the following correctly describe patterns of motion in our solar sy
snow_lady [41]

Answer:

(a), (c), (e)  

Explanation:

<em>(a) The Sun and most of the planets rotate in the same direction that the planets orbit.</em>

The Sun and most of the planets rotates in the same direction (counter-clockwise) as a consequence of the conservation of the angular momentum from the could in which they were formed.

However, Venus and Uranus rotate in retrograde motion (clockwise), it is  thought that is due to the collision with an asteroid in the early days of both planets.

<em>(b) Major moons generally have polar orbits, meaning orbits that take them over the north and south poles of the planet they orbit.</em>

Polar orbits are not common between major moons, They follow orbits related to the plane of the Solar System.    

<em>(c) Planets have nearly circular orbits.</em>

Kepler's first law establishes:

<em>All the planets revolve around the Sun in an ellipse orbit, with the Sun in one of the focus.</em>

The ellipse has a low eccentricity in the case of planetary orbits.

<em>(d) The outer planets are so large that they nearly collide with each other on each orbit.</em>

They have enough space between them, so it is not possible a collision.

For example, lets take the example of the diameter on Jupiter and Saturn. The diameter of Jupiter is 139.820 Km while Saturn has a diameter of 116.460 Km.

The distance of Saturn from the Sun is 9.5 AU (AU = Astronomical Unit) while in Jupiter is 5.1 AU.

1 AU is defined as the distance between the Earth and the Sun (1.50x10^{8} Km)

The distance of Saturn from the Sun in Kilometers:  

d_{saturn} = 9.5 AU . \frac{1.50x10^{8} Km}{1AU}

d_{saturn} = 1.425x10^{9} Km

The distance of Jupiter from the Sun in Kilometers:

d_{saturn} = 5.1 AU . \frac{1.50x10^{8} Km}{1AU}

d_{saturn} = 7.65x10^{8} Km

Distance between the two planets:

d_{J-S} = 1.425x10^{9} Km -7.65x10^{8} Km

d_{J-S} = 6.60x10^{8} Km

If the distance between the planets is compared with the diameters of any of them, it is easy to see that the planets can't be in a collision since they don't fill the space between them with its diameter.

In the case of Jupiter:

diameter_{Jupiter} d_{J-S}

139.820 Km 6.60x10^{8}

In the case of Saturn:

diameter_{Saturn} d_{J-S}      

116.460 Km 6.60x10^{8}    

<em>(e)All the planets orbit the Sun in nearly the same plane.</em>

When the cloud, from were the planets form, collapse, it starts to rotate and accrete the material in a disk. Given as a result that the planets were in nearly the same plane.

It is important to consider that planets have different degrees of orbital inclinations, which is due to interactions with others object while its formation.

<em>(f) Inner planets orbit the Sun in the opposite direction from the outer planets </em>

This is not correct. Inner planets are constituted by Mercury, Venus, Earth, and Mars.

Mercury, Earth and Mars share the counter-clockwise direction as some outer planets, while Venus shares the same retrograde motion as Uranus.    

7 0
4 years ago
When an object is falling, its motion is most affected by air resistance when: Check all that apply.
soldier1979 [14.2K]
A and B I'm pretty sure.
5 0
3 years ago
Read 2 more answers
Groupings of mass-produced, cookie-cutter homes are called __________ developments.
Mumz [18]
Groupings of mass-produced, cookie-cutter homes are called tract housing developments.
3 0
3 years ago
A ball with a mass of 3.1 kg is moving in a uniform circular motion upon a horizontal surface. The ball is attached at the cente
inessss [21]

Answer:

3.46 seconds

Explanation:

Since the ball is moving in circular motion thus centripetal force will be acting there along the rope.

The equation for the centripetal force is as follows -

F=\frac{mv^2}{r}

Where, m is the mass of the ball, v is the speed and r is the radius of the circular path which will be equal to the length of the rope.

This centripetal force will be equal to the tension in the string and thus we can write,

20.4 = \frac{3.1\times v^2}{2}

and, v^2 = 13.16

Thus, v = 3.63 m/s.

Now, the total length of circular path = circumference of the circle

Thus, total path length = 2πr = 2 × 3.14 × 2 = 12.56 m

Time taken to complete one revolution = \frac{\text {Path length} }{\text {Speed}} = \frac{12.56}{3.63} = 3.46 seconds.

Thus, the mass will complete one revolution in 3.46 seconds.

4 0
3 years ago
Learning Goal: To practice Problem-Solving Strategy 7.2 Problems Using Mechanical Energy II. The Great Sandini is a 60.0-kg circ
andreev551 [17]

Answer:

v = 15.8 m/s

Explanation:

Let's analyze the situation a little, we have a compressed spring so it has an elastic energy that will become part kinetic energy and a potential part for the man to get out of the barrel, in addition there is a friction force that they perform work against the movement.  So the variation of mechanical energy is equal to the work of the fictional force

    W_{fr} = ΔEm = Em_{f} -Em₀

Let's write the mechanical energy at each point

Initial

    Em₀ = Ke = ½ k x²

Final

   Em_{f} = K + U = ½ m v² + mg y

Let's use Hooke's law to find compression

    F = - k x

    x = -F / k

    x = 4400/1100

    x = - 4 m

Let's write the energy equation

    fr d = ½ m v² + mgy - ½ k x²

Let's clear the speed

   v² = (fr d + ½ kx² - mg y) 2 / m

   v² = (40 4.00 + ½ 1100 4² - 60.0 9.8 2.50)   2/60.0

   v² = (160 + 8800 - 1470) / 30

   v = √ (229.66)

   v = 15.8 m/s

5 0
4 years ago
Read 2 more answers
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