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4 years ago

A toy car with a mass of 2.35 kg is pushed with a force of 21.6 N. What is the acceleration of the car?

Physics

1 answer:

stiv31 [10]4 years ago

6 0

Answer:

a = 9.19m/s^2

Explanation:

Force = mass x acceleration

Given

Force = 21.6N

Mass = 2.35kg

Therefore

21.6 = 2.35 x a

Divide both sides by 2.35

21.6/2.35 = 2.35/2.35 x a

9.19 = a

a = 9.19m/s^2

The acceleration of the car is 9.19m/s^2

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An Atwood machine consists of two masses, mA = 6.8 kg and mB = 8.0 kg , connected by a cord that passes over a pulley free to ro

Lisa [10]

To solve this problem it is necessary to apply the concewptos related to Torque, kinetic movement and Newton's second Law.

By definition Newton's second law is described as

F= ma

Where,

m= mass

a = Acceleration

Part A) According to the information (and as can be seen in the attached graph) a sum of forces is carried out in mass B, it is obtained that,

$\sum F = m_b a$

$m_Bg-T_B = m_Ba$

$T_B = m_Bg-m_Ba$

In the case of mass A,

$\sum F = m_A a$

$T_A = m_Ag-m_Aa$

Making summation of Torques in the Pulley we have to

$\sum\tau = I\alpha$

$T_BR_0-T_AR_0=I\alpha$

$T_B-T_A=I\frac{a}{R^2_0}$

Replacing the values previously found,

$(m_Bg-m_Ba )-(m_Ag-m_Aa )=I\frac{a}{R^2_0}$

$(m_B-m_A)g-(m_B+m_A)a=I\frac{a}{R^2_0}$

$a = \frac{(m_B-m_A)g}{\frac{I}{R_0^2}+(m_B+m_A)}$

$a = \frac{(m_B-m_A)g}{\frac{MR^2_0^2/2}{R_0^2}+(m_B+m_A)}$

$a =\frac{(m_B-m_A)g}{\frac{M}{2}+(m_B+m_A)}$

Replacing with our values

$a =\frac{(8-6.8)(9.8)}{\frac{0.8}{2}+(8+6.8)}$

$a=0.7736m/s^2$

PART B) Ignoring the moment of inertia the acceleration would be given by

$a' =\frac{(m_B-m_A)g}{(m_B+m_A)}$

$a' =\frac{(8-6.8)(9.8)}{(8+6.8)}$

$a' = 0.7945$

Therefore the error would be,

$\%error = \frac{a'-a}{a}*100$

$\%error = \frac{0.7945-0.7736}{0.7736}*100$

$\%error = 2.7%$

8 0

3 years ago

Gaussian surfaces A and B enclose the same positive point charge. The area of surface A is two times larger than that of surface

svlad2 [7]

Answer:

The total electric flux through the two surfaces is equal.

Explanation:

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4 years ago

What is the radioactive element used in nuclear war heads

diamong [38]

Answer:

Plutonium, has formula Pu with molecular mass 94

Explanation:

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3 years ago

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Why alloys<br> are useful to someone with no science<br> knowledge<br><br> Will give Brainiest

Andreyy89

Answer:

The key idea behind the synthesis, processing and application of alloys consist in combining desire qualities from each mineral component in the form of a material.

Explanation:

The key idea behind the synthesis, processing and application of alloys consist in combining desire qualities from each mineral component in the form of a material. For example, steel is the combination of iron, which is ductile but prone to rusting in wet environments, and carbon, which offers high hardness and additional resistence to rusting in wet environments, but is fragile. Hence, steel is more resistant to rusting, ductile as iron and more resistant than iron.

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3 years ago

Three Carnot engines operate between the following temperature limits.

Kipish [7]

Answer:c>a>b

Explanation:

Given

All the engine extracts same amount of heat(Q) from High-temperature reservoir

For a) 400 and 500 K

$\eta _{engine}=1-\frac{T_L}{T_H}$