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Alexus [3.1K]
3 years ago
8

A ball with a mass of 3.1 kg is moving in a uniform circular motion upon a horizontal surface. The ball is attached at the cente

r to a nail with a 2.0-m long rope and the tension in the rope is 20.4 N. Assuming no friction is taking place, how long does it take for the mass to make one complete revolution
Physics
1 answer:
inessss [21]3 years ago
4 0

Answer:

3.46 seconds

Explanation:

Since the ball is moving in circular motion thus centripetal force will be acting there along the rope.

The equation for the centripetal force is as follows -

F=\frac{mv^2}{r}

Where, m is the mass of the ball, v is the speed and r is the radius of the circular path which will be equal to the length of the rope.

This centripetal force will be equal to the tension in the string and thus we can write,

20.4 = \frac{3.1\times v^2}{2}

and, v^2 = 13.16

Thus, v = 3.63 m/s.

Now, the total length of circular path = circumference of the circle

Thus, total path length = 2πr = 2 × 3.14 × 2 = 12.56 m

Time taken to complete one revolution = \frac{\text {Path length} }{\text {Speed}} = \frac{12.56}{3.63} = 3.46 seconds.

Thus, the mass will complete one revolution in 3.46 seconds.

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Why would physics be used to study light emitted by a star?
VARVARA [1.3K]

Answer:

O D.

Explanation:

Physics has an aspect that deals with the study of energy

8 0
3 years ago
4. Derive<br>the relation, P= hd g​
Sergeu [11.5K]

p=F/A

or,P=d×V×G/A (m=d×V)

or,p= d× A×h×g/A (A and A are cut)

or,P=d×H×G

4 0
3 years ago
if a car that is 100 feet in front of you on route 70 west slams on the brakes while you are traveling 65 miles per hour (95 fee
fenix001 [56]

Answer:

t = 1.05 s

Explanation:

Given,

The distance between your vehicle and car, 100 ft

The constant speed of your vehicle, u = 95 ft/s

Since, the velocity is constant, a =0

If the car stopped suddenly, time left for you to hit the brake, t = ?

Using the second equation of motion,

                           S = ut + ½ at²

Substituting the given values in the equation

                           100 = 95 x t

                             t = 100/95

                               = 1.05 s

Hence, the time left for you to hit the brakes and stop before rear ending them, t = 1.05 s

5 0
3 years ago
A bullet leaves a gun with a horizontal velocity of 100 m/s. Calculate the distance it would travel in 1.3 seconds.
stiks02 [169]

Ignoring air resistance, the bullet's horizontal velocity is constant:

v_x=v_{0x}=100\,\dfrac{\mathrm m}{\mathrm s}

In 1.3 seconds, we can expect it to travel

v_xt=\left(100\,\dfrac{\mathrm m}{\mathrm s}\right)(1.3\,\mathrm s)=130\,\mathrm m

4 0
3 years ago
A 8.2-V battery is connected in series with a 38-mH inductor, a 150-Ω resistor, and an open switch.A 8.2-V battery is connected
tigry1 [53]

Answer:

(A). The current in the circuit is 19.25 mA.

(B). The store energy in the inductor is 7.04 μJ.

Explanation:

Given that,

Voltage = 8.2 V

Inductor = 38 mH

Resistance = 150 Ω

Time t = 0.110 ms

The battery has negligible internal resistance, so that the total resistance  in the circuit is 150 ohms. Then use this equation for current at time t in terms of inductance

We need to calculate the current

Using formula of current

I(t)=\dfrac{V}{R}\times(1-e^{-t\times\dfrac{R}{L}})

Put the value into the formula

I(t)=\dfrac{8.2}{150}\times(1-e^{-0.110\times10^{-3}\times\dfrac{150}{38\times10^{-3}}})

I(t)=0.01925\ A

I(t) = 19.25\ mA

(B). We need to calculate the store energy in the inductor

Using formula of energy

E=\dfrac{1}{2}LI^2

Put the value into the formula

E=\dfrac{1}{2}\times38\times10^{-3}\times(0.01925)^2

E=7.04\times10^{-6}\ J

{tex]E=7.04\ \mu J[/tex]

Hence, (A). The current in the circuit is 19.25 mA.

(B). The store energy in the inductor is 7.04 μJ.

8 0
3 years ago
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