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Alexus [3.1K]
3 years ago
8

A ball with a mass of 3.1 kg is moving in a uniform circular motion upon a horizontal surface. The ball is attached at the cente

r to a nail with a 2.0-m long rope and the tension in the rope is 20.4 N. Assuming no friction is taking place, how long does it take for the mass to make one complete revolution
Physics
1 answer:
inessss [21]3 years ago
4 0

Answer:

3.46 seconds

Explanation:

Since the ball is moving in circular motion thus centripetal force will be acting there along the rope.

The equation for the centripetal force is as follows -

F=\frac{mv^2}{r}

Where, m is the mass of the ball, v is the speed and r is the radius of the circular path which will be equal to the length of the rope.

This centripetal force will be equal to the tension in the string and thus we can write,

20.4 = \frac{3.1\times v^2}{2}

and, v^2 = 13.16

Thus, v = 3.63 m/s.

Now, the total length of circular path = circumference of the circle

Thus, total path length = 2πr = 2 × 3.14 × 2 = 12.56 m

Time taken to complete one revolution = \frac{\text {Path length} }{\text {Speed}} = \frac{12.56}{3.63} = 3.46 seconds.

Thus, the mass will complete one revolution in 3.46 seconds.

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The time taken to hit the ground is 3.9 s, the range is 18m and the final velocity is 42.82 m/s

<h3>Motion Under Gravity</h3>

The motion of an object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.

Given that a ball is thrown horizontally from the roof of a building 75 m tall with a speed of 4.6 m/s.

a. how much later does the ball hit the ground?

The time can be calculated by considering the vertical component of the motion with the use of formula below.

h = ut + 1/2gt²

Where

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  • Initial velocity u = 0 ( vertical velocity )
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Substitute all the parameters into the formula

75 = 0 + 1/2 × 9.8 × t²

75 = 4.9t²

t² = 75/4.9

t² = 15.30

t = √15.3

t = 3.9 s

b. how far from the building will it land?

The range can be found by using the formula

R = ut

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R = 4.6 × 3.9

R = 18 m

c. what is the velocity of the ball just before it hits the ground?

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v = u + gt

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v = 4.6 + 38.22

v = 42.82 m/s

Therefore, the answers are 3.9 s, 18 m and 42.82 m/s

Learn more about Vertical motion here: brainly.com/question/24230984

#SPJ1

7 0
1 year ago
a 0.40kg soccer ball approaches a player horizontally with a velocity of 18m/s north. the player strikes the ball and causes it
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Impulse = Ft = (m)(delta v)
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As a wave moves through a medium, particles are displaced and (2 points)
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As a wave moves through a medium, particles are displaced and return to their normal position after the wave passes.

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As waves travel through matter, they will temporarily  displace the molecules or particles in matter up-and-down  or side-to-side. Waves move the energy but they do not  carry the matter with them longitudinally as they move  through matter. Once the disturbance passes, the medium  will return to its original state or position.

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