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2 years ago

How does heat move between objects that are touching?

Chemistry

1 answer:

Tom [10]2 years ago

6 0

Answer:

Conduction

Explanation:

Conduction is heat transfer between two objects that are touching each other. When two objects touch and one has a higher temperature than the other; heat is transferred to the object with the lower temperature. ... In radiation, heat is transferred from one object to another by electromagnetic waves of energy. Edit : Please mark brainliest if it helped, thanks.

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Based on graph 4 across a period the electronegativity

Romashka-Z-Leto [24]

4

Answer with explanation

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3 years ago

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What are the missing coefficients for H3PO4 + HCl = PCl5 + H2o

grigory [225]

Answer:

H3PO4 + 5 HCl → PCl5 + 4 H2O

Explanation:

The given equation is

H3PO4 + HCl = PCl5 + H2O

The above chemical equation has one P atom on both the sides, hence phosphorus is balanced

There are 5 Cl on the RHS but only one Cl on the LHS. On balancing the chlorine, we get -

H3PO4 + 5HCl = PCl5 + H2O

Now, there are 8 hydrogen atom on the LHS but only two on the RHS. On balancing the hydrogen on both the sides, the new equation become

H3PO4 + 5HCl = PCl5 + 4H2O

Let us check for oxygen

Oxygen on LHS = 4 and oxygen on RHS = 4

Thus, the balanced equation is H3PO4 + 5HCl = PCl5 + 4H2O

7 0

3 years ago

Please help me with chemistry

jok3333 [9.3K]

I will, I am in a chemistry class right now. What’s up?

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3 years ago

When rubidium ions are heated to a high temperature, two lines are observed in its line spectrum at wavelengths (a) 7.9 × 10−7 m

svetlana [45]

Answer:

The frequencies of the two lines are:

a) $3.79\times 10^{14} s^{-1}$

b) $7.14\times 10^{14} s^{-1}$

When we heat rubidium compound we will see red color.

Explanation:

$\nu=\frac{c}{\lambda }$

c = speed of light

$\lambda$ = wavelength of light

a) Frequency of the light when wavelength is equal to $7.9\times 10^{-7} m$

$\nu=\frac{c}{\lambda }$

$\nu=\frac{3\times 10^8m/s)}{7.9\times 10^{-7}}$

$\nu=3.79\times 10^{14} s^{-1}$

This frequency corresponds to red light

b) Frequency of the light when wavelength is equal to $4.2\times 10^{-7} m$

$\nu=\frac{c}{\lambda }$

$\nu=\frac{3\times 10^8m/s)}{4.2\times 10^{-7}}$

$\nu=7.14\times 10^{14} s^{-1}$

This frequency corresponds to violet light

When we heat rubidium compound we will see red color.

4 0

3 years ago

A solid reactant is placed into a beaker of a warm water. The liquid vigorously bubbles as the solid dissolves into the solution

Nataly [62]

Answer:

Fewer bubbles will be produced because of fewer collisions of reactant molecules

Explanation:

As the solid dissolves into the solution after the liquid has been vigorously bubbled, if the temperature of the liquid is reduced a little, what will happen is that fewer bubbles will be produced as a result of lesser amount of collisions occurring between the reactant molecules

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3 years ago