How many moles of O2 are required to generate 18 moles of H2O in the given reaction? 2C8H18 + 25O2 16CO2 + 18H2O
2 answers:
<u>Answer:</u> 25 moles of oxygen gas will be required for the production of given amount of water.
<u>Explanation:</u>
This is a reaction of combustion of hydrocarbon. Combustion reaction states that when a hydrocarbon reacts with excess of oxygen it results in the formation of carbon dioxide and water.
For the reaction of combustion of hydrocarbon, the equation follows:
By Stoichiometry of the reaction:
18 moles of water is produced by 25 moles of oxygen gas.
So, 18 moles of water will be produced from = of oxygen gas.
Hence, 25 moles of oxygen gas will be required for the production of given amount of water.
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Answer:
Kp = 1.41 x 10⁻⁶
Explanation:
We have the chemical equation:
2 A(g) + 3 B(g)⇌ C(g)
In which A and B are the reactants and C is the product. We calculate first the change in the number of moles of gas (Δn or dn):
dn= (sum moles products - sum moles reactants)
= (moles C - (moles A + moles B))
= (1 - (2+3))
= 1 - 5
= -4
We have also the following data:
Kc = 63.2
T= 81∘C + 273 = 354 K
R = 0.082 L.atm/K.mol (it is a constant)
Thus, we introduce the data in the mathematical expression for the relation between Kp and Kc:
= (0.082 L.atm/K.mol x 354 K)⁻⁴ = 1.41 x 10⁻⁶