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zhenek [66]
3 years ago
9

a paraellel plate capacitor consists of 2 large circular sheets of metal separated by 1.53 cm. The electric field energy density

betwwen plates is 4.41 J/m3 while the capacitor holds .127 J of potential energy. What is the radius of the circular platyes?
Physics
1 answer:
natita [175]3 years ago
6 0

Answer:

The radius of the circular plate is 0.774 m

Explanation:

Given;

distance between the parallel plates, d = 1.53 cm = 0.0153 m

electric field energy density between plates, U_E  = 4.41 J/m³

Potential energy of the capacitor, U_c = 0.127 J

Energy density is given as;

U_E = \frac{U_c}{V}

where;

V is volume

V = \frac{U_c}{U_E} = \frac{0.127}{4.41} = 0.0288 \ m^3

Volume is given as;

V = Ad

where;

A is area

A = V / d

A = (0.0288) / (0.0153)

A = 1.882 m²

Area of circular plate is given as;

A = πr²

where;

r is the radius of the circular plate

r = \sqrt{\frac{A}{\pi} } \\\\r = \sqrt{\frac{1.882}{\pi}}\\\\r = 0.774 \ m

Therefore, the radius of the circular plate is 0.774 m

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a cone is constructed by cutting a sector from a circular sheet of metal with radius . the cut sheet is then folded up and welde
Svet_ta [14]

The expression for the radius and height of the cone can be obtained from

the property of a function at the maximum point.

  • The \ radius, \ of \ the \ base \ of \ the \ cone \ is \ \sqrt{ \dfrac{3}{4}} \times radius \ of \ circular \ sheet \ metal
  • The height of the cone is half the length of the radius of the circular sheet metal.

Reasons:

The part used to form the cone = A sector of a circle

The length of the arc of the sector = The perimeter of the circle formed by the base of the cone.

Volume \ of \ a \ cone = \dfrac{1}{3} \cdot  \pi \cdot r^3 \cdot h

  • Volume \ of \ a \ cone, \, V = \dfrac{1}{3} \cdot  \pi \cdot r^3 \cdot \sqrt{(s^2- r^2)}

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Where;

s = The radius of he circular sheet metal

h = s² - r²

  • \dfrac{dV}{dr} = \dfrac{d}{dr}  \left(\dfrac{1}{3} \cdot  \pi \cdot r^3 \cdot \sqrt{(s^2- r^2)}\right) = \dfrac{\pi \cdot (3 \cdot r^2 \cdot  s^2 - 4 \cdot r^4)}{\sqrt{(s^2- r^2)}} = 0

3·r²·s² - 4·r⁴ = 0

3·r²·s² = 4·r⁴

3·s² = 4·r²

\underline{\left  \right. The \ radius, \, r =\sqrt{ \dfrac{3}{4}} \cdot s}

\underline{The \ height, \, h =\sqrt{s^2 - \dfrac{3}{4}\cdot s^2} = \dfrac{s}{2}}}

Learn more here:

brainly.com/question/14466080

3 0
3 years ago
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