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lesya692 [45]
2 years ago
12

SOMEONE HELP ME PLEASE WITH THESE PROBLEMS AND PLEASE SHOW YOUR WORK FOR 50 points and BRAINLIEST THANK YOU

Mathematics
2 answers:
statuscvo [17]2 years ago
8 0

Solution:

<u>Question 13:</u>

  • 12x⁹y⁵/2x²y⁻²
  • => 6x⁹y⁵/x²y⁻²
  • => 6x⁹⁻²y⁵⁺²
  • => 6x⁷y⁷

<u>Question 14:</u>

  • (5y⁻³/x⁻²)²
  • => (25y⁻⁶/x⁻⁴)
  • => 25x⁴y⁻⁶

Hoped this helped!

ELEN [110]2 years ago
4 0

<u>Answer</u>:

13. 6x^7 y^7   ||     14. \frac{25x^4}{y^6}

<u>explanation</u>:

13.

\frac{12x^9 y^5}{2x^2 y^-2}

6x^{9-2} y^{5--2}

6x^7 y^7

14.

(\frac{5y^{-3} }{x^{-2} } )^{2}

(\frac{5y^{-3} }{x^{-2} } )(\frac{5y^{-3} }{x^{-2} } )

\frac{\frac{25}{y^6}}{\left(x^{-2}\right)^2}

\frac{\frac{25}{y^{-6} }}{\left(x^{-4}\right)}

\frac{25x^4}{y^6}

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Nookie1986 [14]

Answer:

n = \frac{2}{3}  

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3 0
3 years ago
This was the question it got deleted I just need 1,2,5
scoundrel [369]

Answer:

1. The volume of the cylinder is 263 cm^{3}.

2. The volume of the cylinder is 12 m^{3}.

3. The volume of the cylinder is 3165.1 cm^{3}.

4. The radius of the cylinder is 3.6 cm.

5a. Area of the base is 50.2 cm^{2}.

5b. The curved surface area of the pencil holder is 351.7 cm^{2}.

5c. The surface are of the pencil holder is 452.2 cm^{2}.

Step-by-step explanation:

1. The given shape is a cylinder, so that;

volume of a cylinder = \pir^{2}h

                                  = 3.14 x (3.8)^{2} x 5.8

                                  = 262.98128

The volume of the cylinder is 263 cm^{3}.

2. This is also a cylinder, but with a given diameter.

radius = \frac{diameter}{2}

          = \frac{1.2}{2} = 0.6 m

volume of a cylinder = \pir^{2}h

                                  = 3.14 x (0.6)^{2} x 10.6

                                  = 11.98224

The volume of the cylinder is 12 m^{3}.

3. volume of a cylinder = \pir^{2}h

                                      = 3.14 x 6^{2} x 28

                                      = 3165.12

The volume of the cylinder is 3165.1 cm^{3}.

4. volume of a cylinder = \pir^{2}h

239 = 3.14 x r^{2} x 6

239 = 18.84 r^{2}

r^{2} = \frac{239}{18.84}

   = 12.6858

r = \sqrt{12.6858}

 = 3.5617

The radius of the cylinder is 3.6 cm.

5. Area of the base = \pir^{2}

radius = \frac{diameter}{2}

           = \frac{8}{2} = 4 cm

Area of the base = 3.14 x 4^{2}

                            = 50.24

Area of the base is 50.2 cm^{2}.

5b. Area of the curved surface of the pencil holder = 2\pirh

                                                                    = 2 x 3.14 x 4 x 14

                                                                     = 351.68

The curved surface area of the pencil holder is 351.7 cm^{2}.

5c. Surface area of the pencil holder = 2\pirh + 2\pir^{2}

                               = 2\pir(h + r)

                                = 2 x 3.14 x 4 (14 + 4)

                                = 452.16

The surface are of the pencil holder is 452.2 cm^{2}.

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UkoKoshka [18]

Answer:

Step-by-step explanation:

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1. What are the roots of this equation? x2 + 4x + 8 = 0 A. –1 + i B. –4 +1 C. –2 + 21 D. -1 + 4​
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Answer:

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Step-by-step explanation:

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