Alice purchased paint in a bucket with a radius of 9 in. and a height of 9.5 in. The paint cost $0.09 per in3.

Plot point C(2,7). If M is the midpoint of CD , what are the coordinates of D?

Y_Kistochka [10]

Answer:

The coordinates of D is (-4,-9)

Step-by-step explanation:

Given

C = (2,7)

M=(-1,-1) ----- Missing part of question

Required

Determine the coordinates of D

Let the coordinates of D be (x₂,y₂)

We'll solve this question using mid point formula;

$M(x,y) = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Where

$C(x_1,y_1) = (2,7)$ and $M(x,y) = (-1,-1)$

Put these values in the formula

$(-1,-1) = (\frac{2+x_2}{2},\frac{7+y_2}{2})$

By comparison;

$-1 = \frac{2+x_2}{2}$ and $-1 = \frac{7+y_2}{2}$

$-1 = \frac{2+x_2}{2}$

Multiply both sides by 2

$-2 = 2 + x_2$

Subtract 2 from both sides

$-2 -2 = x_2$

$x_2 = -4$

$-1 = \frac{7+y_2}{2}$

Multiply both sides by 2

$-2 = 7 + y_2$

Subtract 7 from both sides

$-2 - 7 = y_2$

$y_2 = -9$

Hence, the coordinates of D is (-4,-9)

4 0

3 years ago

Standard deviation of 300, 785, 670, 187, 760, 724

White raven [17]

STEP 1

Mean = $\frac{300+785+670+187+760+724}{6} = \frac{3426}{6}=571$

STEP 2

Subtract the mean from each data value then square the answer
$300-571=-271$ ⇒ $(-271)^{2} =73441$
$785-571=214$ ⇒ $(214)^{2}=45796$
$670-571=99$ ⇒ $(99)^{2}=9801$
$187-571=-384$ ⇒ $(-384)^{2} =147456$
$760-571=189$ ⇒ $189^{2}=35721$
$724-571=153$ ⇒ $153^{2} =23409$

STEP 3

Add the squared answers in STEP 2 then find the mean

$\frac{73441+45796+9801+147456+35721+23409}{6}= \frac{335624}{6}=55937.3$

STEP 4

Square root the answer in STEP 3
$\sqrt{55937.3} =236.5$

Standard deviation is 236.5

7 0

3 years ago

Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg lesss strawberries in the morning tha in the afte

Tpy6a [65]

Answer:

$3\frac{13}{20}=3.65$ kg.

Step-by-step explanation:

Let S be amount of strawberries picked in the afternoon.

We have been given that Sheldon harvest the strawberries and tomatoes in his garden. He picks 1 2/5 kg less strawberries in the morning than in the afternoon and the strawberries picked in morning are $2\frac{1}{4}$ kg.