Answer
Step-by-step explanation:
The first graph is c. c - 7 < 3.
The second graph is a. c + 7 ≤ 3.
The third graph is b. c - 3 > 1.
Answer:
- Perimeter = 22*sqrt(2)
- Area = 60.5 inches
- D
Step-by-step explanation:
Remark
You need 2 facts.
- A square has 4 equal sides.
- It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.
That means you can use the Pythagorean Theorem.
If one side of a square is a then the 1 after it is a as well.
Formula
- a^2 + a^2 = c^2
- 2a^2 = c^2
Givens
Solution
- 2a^2 = 11^2
- 2a^2 = 121 Divide by 2
- a^2 = 121/2 Take the square root of both sides
- sqrt(a^2) = sqr(121/2)
- a = 11/sqrt(2) Rationalize the denominator
- a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
- a = 11 * sqrt(2) / 2
<em><u>Perimeter</u></em>
P = 4s
- P = 4*11*sqrt(2)/2
- P = 44*sqrt(2)/2
- P = 22*sqrt(2)
You don't need the area. The answer is D
<em><u>Area</u></em>
- Area = s^2
- Area = (11*sqrt(2)/2 ) ^2
- Area = 121 * 2 / 4
- Area = 60.5
Answer:
case a) 
----> open up
case b) 
----> open down
case c) 
----> open left
case d) 
----> open right
Step-by-step explanation:
we know that
1) The general equation of a vertical parabola is equal to
where
a is a coefficient
(h,k) is the vertex
If a>0 ----> the parabola open upward and the vertex is a minimum
If a<0 ----> the parabola open downward and the vertex is a maximum
2) The general equation of a horizontal parabola is equal to
where
a is a coefficient
(h,k) is the vertex
If a>0 ----> the parabola open to the right
If a<0 ----> the parabola open to the left
Verify each case
case a) we have
so
so
therefore
The parabola open up
case b) we have
so
therefore
The parabola open down
case c) we have
so
therefore
The parabola open to the left
case d) we have
so
therefore
The parabola open to the right
Answer:
i hope this works. Feel better soon!
Step-by-step explanation:
1.SAS 2 AAS 3 SAS 4 NOT CONGRUENT 5 SSS 6 ASA
7. ∠BAC≅∠EDC given, BC ≅ CE GIVEN ∠ACB≅∠DCE VERTICAL ANGLES, ΔABC≅ΔDEC AAS
8. ∠PQR≅∠TSR GIVEN R IS MIDPOINT OF PT GIVEN PQ≅ST GIVEN ΔPQR≅ΔTSR HYPOTENUSE LEG THEORUM
9. AC BISECTS BCD GIVEN ∠ABD≅∠ADC GIVEN ∠ACB≅∠ADC BISECTED ANGLES AC≅AC REFLEXIVE PROPERTY OF CONGRUENCE ΔABC≅ΔADC ASA AB≅AC SAME SIDES OF CONGRUENT TRIANGLES
