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2 years ago

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17. Paige has 5 more toys than Jordan and 8 more toys than Bill. Altogether, the three friends have 20 toys. How many toys does

Jordan have? (A) 6 (B) 8 (C) 11 (D) 16

1 answer:

Lelechka [254]2 years ago

8 0

trick question, its 7...

Step-by-step explanation:

You might be interested in

Suppose you got 8 mangoes and 3 apples for $18 and 3 mangoes and 5 apples for $14.50.

Mandarinka [93]

Let x = cost of mango
y = c of apples
<span>8x+3y=18.
3x+5y=14.5 </span>

<span> </span>
<span>24x+9y=54
24x+40y=116
multiplying them with 3 and 8 resectively. </span>
<span>subtract one from the other we get </span>
<span>40y-9y=116-54 </span>
<span>31y=62 </span>
<span>y=2.
cost of apple=2$ per apple
</span><span>8x+3y=18,
8x+3(2)=18.
8x=12. x=12/8=1.5 </span>
<span>cost of mango i= 1.5 $ per mango
hope this helps</span>

7 0

3 years ago

Solve each quadratic equation by factoring and check

max2010maxim [7]

hello : <span>
<span>the discriminat of each quadratic equation : ax²+bx+c=0 ....(a ≠ 0) is :
Δ = b² -4ac
1 ) Δ > 0 the equation has two reals solutions : x1,2 = (-b±√Δ)/2a</span></span>

factoring :

<span>ax²+bx+c = a(x-x1)(x-x2)
2 ) Δ = 0 : one solution : x1 = x2 = -b/2a</span>

factoring :

<span>ax²+bx+c = a(x-x1)²
3 ) Δ < 0 : no reals solutions... no </span>

<span>factoring </span>

5 0

3 years ago

sitting on park bench, you see a swing that is 60 feet away and a slide that is 80 feet away. The angle between them is 30 degre

Snowcat [4.5K]

I would use the Pythagorean theorem

4 0

3 years ago

Read 2 more answers

HEEEELP WILL GIVE BRAINLIEST

IrinaK [193]

Answer:

Yes

Step-by-step explanation:

3/6 = 12/24

3 0

3 years ago

Read 2 more answers

Question 1,2, and 3 how do i factor those? Can you show the work and explain how?

DiKsa [7]

1: $3n^{2}+9n+6$

notice that each part is divisible by 3

$3n^{2}$ ÷ 3 = $n^{2}$

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes $3(n^{2} +3n+2)$

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

$3(n^{2} +2n+n+2)$

Now that it's rewritten, you can factor out n + 2 from the equation.

<u><em>the answer is </em></u>

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is $n^{2} +2n+n+2$ and then each of those by 3, which is $3n^{2} +6n+3n+6$ or $3n^{2}+9n+6$ , our origional equation

2: $28+x^{2} -11x$

So I rewrote this as $x^{2} -11x+28$ (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

$x^{2} -4x-7x+28$

now we can factor out x from the first expression and -7 from the second

$x(x-4)-7(x-4)$

and lastly you factor out x-4,

<u><em>which would give you</em></u>

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to $x^{2} -11x+28$

3: $9x^{2} -12x+4$

The first thing I notice when looking at this problem is that both 9 and 4 are perfect squares. Not only that, but they are the squares of 2 and 3, which are products of -12

So if you rewrite 9 as $3^{2}$ and 4 as $2^{2}$ , the equation becomes

$3^{2} x^{2} -12x+2^{2}$

now that $3^{2} x^{2}$ is ugly so it can be turned into $(3x)^{2}$

and -12x can be rewritten as $-2*3x*2$

so our equation now looks like $(3x)^2-2*3x*2+2^{2}$

There's a rule that says $a^{2} -2ab+b^{2} = (a-b)^{2}$

In our case, a=3x and b=2

<u><em>so the final answer is</em></u>

$(3x-2)^2$

5 0

2 years ago