All categories

3 years ago

The perimeter of a square in which A=169cm square root 2?

1 answer:

7 0

I'm guessing you mean:
$A = 169 \sqrt{2}$

If not, correct me.

So, then the perimeter of a square is just 4*A, which in this case would be:
$4(169 \sqrt{2}) = 676 \sqrt{2}$

And that would be your answer: $676 \sqrt{2}$ units²

You might be interested in

By selling a table for sh.56, gain is as much as percent as its cost in dollars. What is the cost price? By selling a table for

sergij07 [2.7K]

The cost price of the table is $40.

Gain is the amount gain by selling the product at a higher price than its cost.

Let the cost of the table is $ x

The percentage gain is x% (as given in the question)

Cost price = ?

It is known that

Step 1 : Gain = ( selling Price - Cost Price) * 100 / Cost Price

Selling price = 56

Cost Price = $ x

Therefore substituting the value

x = (56 - x) * 100 / x

x² = 5600 - 100x

x² +100x -5600 = 0

Step 2 : Factorizing

x² + 140x - 40 x -5600 = 0

x( x+14 ) -40( x +14) = 0

( x - 40)(x +14) = 0

x = $40

Therefore the cost price of the table is $40.

To know more about Gain

brainly.com/question/23385214

#SPJ1

3 0

2 years ago

Jack biked to his friend house at a speed of 10 mph. When he was returning home it was raining. So he biked much slower - at 6 m

AVprozaik [17]

Answer:

7.5

Step-by-step explanation:

The relation between time, speed, and distance is ...

time = distance/speed

If distance is "1 round trip", then the time going is ...

going = 0.5/(10 mi/h) . . . . for 1/2 round trip

and the time coming is ...

coming = 0.5/(6 mi/h)

Then the average speed for the full round trip is ...

speed = distance/time

average speed = 1/(going + coming) = 1/(0.5/10 +0.5/6) mi/h

= 1/((3+5)/60) mi/h

= 60/8 mi/h = 7.5 mi/h

Jack's average speed for the round trip was 7.5 mph.

7 0

2 years ago

Which of the following equations describes the line shown below? Check all<br> that apply.

kondaur [170]

Answer:

B and C

Step-by-step explanation:

Slope: 4-(-1)/-3-(-1)

Slope: 5/-2

Slope:-5/2

Point Slope form: y+1=-5/2(x+1)

Point Slope form: y-4=-5/2(x+3)

Correct answers are B and C

7 0

2 years ago

Really need help with this question ASAP!!!

Leya [2.2K]

H=-5(t^2 - 16t)

H=-5(t^2 - 16t +64)+320

H=-5(t-8)^2 +320

Vertex is at (8, 320)

The max height is 320 m.

4 0

3 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is:

$P(C) = (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7 + (\frac{1}{3}) ^ 7\\\\P(C) = \frac{1}{729}$

D. The probability is $\frac{1}{729}$ . This number is quite close to zero. Therefore it is an unlikely bastate event.

6 0

3 years ago