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katovenus [111]
2 years ago
13

A mechanic uses a wrench that is 22 cm long to tighten a spark plug. If the mechanic exerts a force of 58 N to the end of the wr

ench, what is the maximum torque she can apply to the spark plug
Physics
1 answer:
Licemer1 [7]2 years ago
4 0

The maximum torque she can apply to the spark plug is 12.76 Nm.

<h3>What is torque?</h3>

Torque is the rotational equivalent of linear force obtained by taking the product of force and the radius of the applied force.

τ = Fr

where;

  • F is the applied force
  • r is the radius

The maximum torque she can apply to the spark plug is calculated as follows;

τ = 58 x (0.22)

τ = 12.76 Nm

Thus, the maximum torque she can apply to the spark plug is 12.76 Nm.

Learn more about torque here: brainly.com/question/14839816

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Explanation: The impulse experienced by the object equals the change in momentum of the object. In equation form, F • t = m • Δ v
5 0
3 years ago
A current of 5 A is flowing in a 20 mH inductor. The energy stored in the magnetic field of this inductor is:_______
Kipish [7]

Answer:

C. 0.25J

Explanation:

Energy stored in the magnetic field of the inductor is expressed as E = 1/2LI² where;

L is the inductance

I is the current flowing in the inductor

Given parameters

L = 20mH = 20×10^-3H

I = 5A

Required

Energy stored in the magnetic field.

E = 1/2 × 20×10^-3 × 5²

E = 1/2 × 20×10^-3 × 25

E = 10×10^-3 × 25

E = 0.01 × 25

E = 0.25Joules.

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7 0
3 years ago
In this example we see how thermal expansion can actually throw off the accuracy of a length-measuring device—namely, a tape mea
Ulleksa [173]

Answer:

The new length is 50.00885m

Explanation:

linear thermal expansion coefficient Fe 11.8e-6 /K

The new length can be determined using the following equation:

∆L/L = α∆T, where α is linear thermal expansion coefficient

∆L = Lα∆T = 50(11.8e-6)(35-20) = 0.00885 m

New length = ( 50.000 + 0.00885)m =

New length = 50.00885 m

5 0
3 years ago
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The atomic number of magnesium is 12. This means that its nucleus must contain
nasty-shy [4]
12 protons in the nucleus
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After being struck by a bowling ball, a 1.8 kg bowling pin sliding to the right at 5.0 m/s collides head-on with another 1.8 kg
kaheart [24]

Answer:

a) v₂ = 4.2 m/s

b) v₂ = 5 m/s

Explanation:

a)

We will use the law of conservation of momentum here:

m_1u_1+m_2u_2=m_1v_1+m_2v_2

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0.8 m/s

v₂ = speed of second after before collsion = ?

Therefore,

(1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s

<u>v₂ = 4.2 m/s</u>

<u></u>

b)

We will use the law of conservation of momentum here:

m_1u_1+m_2u_2=m_1v_1+m_2v_2

where,

m₁ = m₂ = mass of bowling pin = 1.8 kg

u₁ = speed of first pin before collsion = 5 m/s

u₂ = speed of second pin before collsion = 0 m/s

v₁ = speed of first pin after collsion = 0 m/s

v₂ = speed of second after before collsion = ?

Therefore,

(1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)

<u>v₂ = 5 m/s</u>

5 0
3 years ago
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