Question

A golfer tees off and hits a golf ball at a speed of 31 m/s and at an angle of 35 degrees. What is the horizontal velocity component of the ball? Round the answer to the nearest tenth of a m/s.

Answer 1

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The vertical velocity (vy) is -569 meter/second.

Answer 2

Answer:

25.4 m/s

Explanation:

When doing a question such as this, always assume the object traveling (a golf ball in this case) travels as a particle, where there is no air resistance.

The golf ball has an initial velocity or 31 m/s, and is hit at an angel of 35°.

When breaking down its velocity into its x and y components, we use different formulas. To acquire the x component of velocity, the following formula is used:

Vₓ = v cos(θ)  (where v is the overall velocity, and theta-θ is the angel at which it is hit)

Using this formula, we can calculate the x component of the velocity:

Vₓ = v cos(θ)

Vₓ = (31 m/s) cos(35)

Vₓ = 25.3937 m/s

Since the question asks to round to the nearest tenth, the final answer is:

Vₓ = 25.4 m/s