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Tju [1.3M]
3 years ago
11

A graph titled velocity versus time has horizontal axis time (seconds) and vertical axis velocity (meters per second). A line ru

ns from 0 seconds 5 meters per second to 5 seconds 25 meters per second. What is the initial velocity of the object represented by the graph? m/s.
Physics
1 answer:
erma4kov [3.2K]3 years ago
5 0

"Initial" means "as our story begins", or "when we arrive", or "when we start watching it", or "at the beginning of time".

You just told us that on the graph, the speed was <em>5 m/s</em> at zero seconds.     So that's the initial speed.

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Vinil7 [7]

reaction, opposite directions, and more

6 0
4 years ago
Read 2 more answers
Two circular loops carry identical currents, but the radius of one loop is twice that of the other.
Valentin [98]

The magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.

Explanation:

The magnetic field strength at the center of a current-carrying circular loop is

B=\frac{\mu_0 I}{2R}

where

\mu_0 is the vacuum permeability

I is the current

R is the radius of the loop

For the first circular loop, we have

B_1 = \frac{\mu_0 I_1}{2R_1}

The second loop has

I_2 = I_1 (same current)

R_2 = 2R_1 (twice the radius)

So, the magnetic field at the centre of the second loop is

B_2 = \frac{\mu_0 I_2}{2R_2}=\frac{1}{2}(\frac{\mu_0 I_1}{2R_1})=\frac{B_1}{2}

So, the magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.

Learn more about magnetic fields:

brainly.com/question/3874443

brainly.com/question/4240735

#LearnwithBrainly

4 0
3 years ago
Given the Earth's density as 5.5 g/cm3 and the Moon's density as 3.34 g/cm3, determine the Roche limit for the Moon orbiting the
Assoli18 [71]

Answer:

The Roche limit for the Moon orbiting the Earth is 2.86 times radius of Earth

Explanation:

The nearest distance between the planet and its satellite at where the planets gravitational pull does not torn apart the planets satellite is known as Roche limit.

The relation to determine Roche limit is:

Roche\ limit=2.423\times R_{P}\times\sqrt[3]{\frac{D_{P} }{D_{M} } }     ....(1)

Here R_{P} is radius of planet and D_{P}\ and\ D_{M} are density of planet and moon respectively.

According to the problem,

Density of Earth,D_{P} = 5.5 g/cm³

Density of Moon,D_{M} = 3.34 g/cm³

Consider R_{E} be the radius of the Earth.

Substitute the suitable values in the equation (1).

Roche\ limit=2.423\times R_{E}\times\sqrt[3]{\frac{5.5 }{3.34 } }

Roche\ limit= 2.86R_{P}

8 0
3 years ago
A cheetah ran 300 feet in 2.92 seconds. What was the cheetah’s average speed in miles per hour?
olganol [36]
We will first convert feet to miles:
1 foot = 0.00018939 miles
300 foot = 0.056817 miles
Than seconds to hours:
2.92 seconds = 0.04867 minutes = 0.0008111 hours
Average speed :
v = d / t
v = 0.056817 miles / 0.008111 h
v = 70.05 miles per hour
6 0
3 years ago
A 2 C charge and a 4 C charge attract each other with 10 N of force How much will a 2C charge and a 8 C charge attract each othe
densk [106]

Answer: 20N

Explanation:

5 0
2 years ago
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