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The magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.
Explanation:
The magnetic field strength at the center of a current-carrying circular loop is

where
is the vacuum permeability
I is the current
R is the radius of the loop
For the first circular loop, we have

The second loop has
(same current)
(twice the radius)
So, the magnetic field at the centre of the second loop is

So, the magnetic field at the center of the 2nd loop is half the magnetic field at the center of the 1st loop.
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Answer:
The Roche limit for the Moon orbiting the Earth is 2.86 times radius of Earth
Explanation:
The nearest distance between the planet and its satellite at where the planets gravitational pull does not torn apart the planets satellite is known as Roche limit.
The relation to determine Roche limit is:
....(1)
Here
is radius of planet and
are density of planet and moon respectively.
According to the problem,
Density of Earth,
= 5.5 g/cm³
Density of Moon,
= 3.34 g/cm³
Consider
be the radius of the Earth.
Substitute the suitable values in the equation (1).
![Roche\ limit=2.423\times R_{E}\times\sqrt[3]{\frac{5.5 }{3.34 } }](https://tex.z-dn.net/?f=Roche%5C%20limit%3D2.423%5Ctimes%20R_%7BE%7D%5Ctimes%5Csqrt%5B3%5D%7B%5Cfrac%7B5.5%20%7D%7B3.34%20%7D%20%7D)

We will first convert feet to miles:
1 foot = 0.00018939 miles
300 foot = 0.056817 miles
Than seconds to hours:
2.92 seconds = 0.04867 minutes = 0.0008111 hours
Average speed :
v = d / t
v = 0.056817 miles / 0.008111 h
v = 70.05 miles per hour