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Ksenya-84 [330]
3 years ago
14

The symbol used for magnetic field is:

Physics
1 answer:
alina1380 [7]3 years ago
5 0
The letter "B" is used for magnetic field
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As the cross-sectional area of a conductor increases, its resistance .
n200080 [17]

Answer:

Yess it’s resistance

Explanation:

8 0
3 years ago
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The images below are models that represent the reactants and products of a chemical reaction.
Eva8 [605]

Explanation:

In a chemical reaction, when mass is conserved , the number of atoms or moles of the reactants must be equal to the number of moles or atoms in the products side.

From the diagram, we should carefully look to see if the number of atoms that makes up the reactants are equal to those on the product side.

 For example:

      A + B → AB

Here, mass is conserved because, on the reactant side, we have 1 atom of A and on the product side we have 1 atom of A

For B, on the reactant side, we have 1 atom of B and on the product side, we have 1 atom of B.

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3 years ago
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Learning Task 2: Prepare a basin with half-filled water and stone. Drop a stone
ELEN [110]

Answer:

1 . What happens when you drop the stone?

Depending on the weight from which the stone was dropped, the glass might well break

2 depending on the size and weight and shape on the stone the glass might well break

3 depending on the density on the stone the stone might when float on the water

Explanition :

GIVE ME BRAINLESS PLEASE !!

6 0
3 years ago
At a rock concert, a dB meter registered 131 dB when placed 2.6 m in front of a loudspeaker on the stage. The intensity of the r
Pavlova-9 [17]

Answer:

Explanation:

A) 131 dB = 10*log(I / 1e-12W/m²)

where I is the intensity at 2.6 m away.

13.1 = log(I / 1e-12W/m²

1.25e13= I / 1e-12W/m²

I = 1.25 x10^1W/m²

power = intensity * area

P = I * A = 12.5W/m² * 4π(2.6m)² =1061 W ◄

B) 86 dB = 10*log(I / 1e-12W/m²)

8.6 = log(I / 1e-12W/m²)

3.98e8 = I / 1e-12W/m²

I = 3.98e-4 W/m²

area A = P / I = 1061W / 3.98e-4W/m² = 2.66e6 m²

A = 4πr²

2.66e6 m² = 4πr²

r = 14.5m ◄

6 0
3 years ago
A ball of 0.5kg slows down from 5m/s to 3m/s. Calculate the work done in the process
ivann1987 [24]
Answer: Cannot determine cause we need to know the change of time to calculate the work.

Explanation:

m = 0.5kg

V = 3m/s - 5m/s = -2m/s

P = W/t = Fv

F = ma

W = Fvt

W = (0.5)(9.8)t = 4.9t



4 0
2 years ago
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