Answer:
The magnitude of the magnetic field is
.
Explanation:
Given that,
Charge, 
Speed of the charged particle, 
The angle between the velocity of the charge and the field is 56°.
The magnitude of force, 
We need to find the magnitude of the magnetic field. When a charged particle moves in the magnetic field, the magnetic force is experienced by it. The force is given by :

B is the magnetic field.

So, the magnitude of the magnetic field is
. Hence, this is the required solution.
Answer:
Choices A, B, and C are correct.
Explanation:
Let us look at each of the choices one by one:
A. It is a vector
Yes. Velocity is a vector, or it's a speed with direction.
B. It is the change in displacement divided by the change in time.
Yes. The velocity can be written as

where
is the displacement—a vector quantity.
C. It can be measured in meters per second.
Yes. The units of velocity are m/s, but also with a unit vector indicating the direction.
D. It is the slope of the acceleration vs. time graph.
Nope. The velocity is the slope of displacement vs. time graph.
Hence, only choices A, B, and C are correct.
Answer:
The acceleration of the wagon is 3 m/s².
To calculate the acceleration of the wagon, we use the formula below.
Formula:
F = ma............. Equation 1
Where:
F = horizontal Force
m = mass of the wagon
a = acceleration of the wagon.
make a the subject of the equation
a = F/m.............. Equation 2
From the question,
Given:
F = 30 N
m = 10 kg
Substitute these values into equation 2
a = 30/10
a = 3 m/s²
Hence, the acceleration of the wagon is 3 m/s².
Answer
given,
tourist travels = 1500 miles
second plane averages 50 miles per hour faster than the first plane.
x = y + 50
The tourist uses the slower plane for the first 500 and the faster plane for the next 1000 miles.
total flying time = 6.5 hours





on solving equation
y = 86.67 mile/hr
x = 86.67 + 50
x = 136.67 mile/hr
Answer:
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Explanation:
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