Answer:
1. will blow because the total current in this circuit is 14 A which is greater than 12 A.
Explanation:
According to Kirchoff current law (KCL) which states that the total current flowing in a circuit is equal to the sum of the individual branch current.
If the supply current is greater than the sum of the individual branch current, then the load will collapse or blow off.
In the question given, the total current of the fuse is 12A
Sum of branch currents = current in branch 1 + current in branch 2
= 8A+6A
= 14A
As we can see that the supply current is lower than the sum of the branch current, this will cause the fuse to blow because some of the branch current will be sent back on the fuse and thereby causing the fuse to blow.
<span>The Answer is 5200 Joules</span>
Answer: 23000 frames/s
Explanation:
We know the <u>maximum initial speed</u> at which the seeds are dispersed is:
In addition, we know the <u>maximum distance at which the seeds move between photographic frames</u> is:
And we need to find the minimum frame rate of the camera with these given conditions. This can be found by finding the time for each frame and then the frame rate:
Finding the time:
This is the time for each frame
Now we need to find the frame rate, which is the frequency at which the photos are taken.
In this sense, frequency is defined as:
Finally:
Hence, the minimum frame rate is 23000 frames per second.
First we determine the motor's efficiency - a ratio of the mechanical output power and the electrical input power:
The output mechanical power is directly proportional to torque and angular speed. From this relationship we can isolate the torque:
whereby the last expression uses the angular speed in rpm units.
(a) we calculate the torque, given that the motor draws 1.2 times the rated current, i.e., 48 Amps:
(b) use formula for the acceleration time:
The startup time will be 0.74s