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iren [92.7K]
3 years ago
6

Properties such as luster, conductivity, and flexibility are used to describe what type of elements

Chemistry
1 answer:
sineoko [7]3 years ago
6 0
Metals
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MgBr2 + NaCl -> MgCl2 + NaBr is the reaction between magnesium bromide and sodium chloride. What type of reaction is this?
valkas [14]

Answer:

Synthesis

Explanation:

I just did the test and got it right!!

4 0
3 years ago
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What must ALWAYS be used to convert between quantities of two different chemical substances?
Vedmedyk [2.9K]

Answer:

Balanced equations and mole ratios

In general, mole ratios can be used to convert between amounts of any two substances involved in a chemical reaction.

Explanation:

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3 years ago
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The density of water at 4 degrees Celsius is 1.000 g/mg is it chemical or physical property?
Kaylis [27]

Answer:

Physical Property

Explanation:

Density, mass, volume, color, melting and boiling points, etc. are all physical properties. No matter what changes, the chemical makeup stays the same.

Flamability, acidity, toxicity, etc. are chemical properties, because they chemically change the makeup of the object/thing.

7 0
3 years ago
Which reaction is more likely to involve a form of combustion (exothermic)? Explain your reasoning.
Andrews [41]

Answer:

The general equation for an exothermic reaction is: Reactants → Products + Energy.

3 0
3 years ago
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What is the mass of 8.12 × 10^23 molecules of CO2 gas? (Atomic mass of carbon = 12.011 u; oxygen = 15.999 u.)
amid [387]

Answer:

m=59.3gCO_2

Explanation:

Hello,

In this case, the first step is to compute the molar mass of carbon dioxide as shown below, considering it has one carbon atom and two oxygen atoms:

M=12.011g/mol+2*15.999g/mol\\\\M=44.009g/mol

It is important to notice it is the mass in one mole of such compound. Afterwards, we need to use the Avogadro's number to compute the how many moles are in the given molecules of carbon dioxide as shown below:

mol=8.12x10^{23}molec*\frac{1mol}{6.022x10^{23}molec} =1.35mol

Finally, the mass by using the molar mass:

m=1.35mol*\frac{44.009g}{1mol} \\\\m=59.3gCO_2

Best regards.

4 0
3 years ago
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