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egoroff_w [7]
2 years ago
8

you know that there are 1609 meter in a mile. the number of feet in a mile is 5280. what is the speed snail from problem 7 per m

inute.
Physics
1 answer:
Zanzabum2 years ago
5 0

Answer:

We know that 1 meter = 100 centimeters, and 1 foot = 12 inches.

So  (1,609 meters) x (100 centimeters/meter)  =  (5,280 feet) x (12 inches/foot)

The second fraction on each side of the equation is equal to ' 1 ', because

the numerator is equal to the denominator, so sticking it in there doesn't

change the value of that side of the equation.  But now we can cancel some

units,and wind up with the units we need.

  (1,609 meters) x (100 centimeters/meter)  =  (5,280 feet) x (12 inches/foot)

        (1,609 x100) centimeters  =  (5,280 x 12) inches

            160,900 centimeters  =  63,360 inches

Divide each side by  63,360 :        2.54 centimeters =  1 inch

Explanation:

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Shah did not trust the results of an experiment that she had read about, so she is conducting the experiment herself. She goes t
Hitman42 [59]

The question is incomplete, the complete question is;

Shah did not trust the results of an experiment that she had read about, so she is conducting the experiment herself. She goes through the same set of steps and measures the effect of the amount of sugar on a single organism.

Which best describes what Shah is doing?

replication

repetition

both repetition and replication

neither repetition nor replication

Answer:

replication

Explanation:

Replication in scientific experiments refer to the process of going through all the steps in an experiment in order to obtain the same set of results initially obtained.

All scientific experiments is expected to be replicated under identical experimental conditions. If the results obtained by a scientific investigation cannot be replicated under identical circumstances by other scientists, then the scientific data must be taken with a pinch of salt.

Shah is expected to obtain almost exactly the same data as the original researchers who first published the data.

5 0
3 years ago
Read 2 more answers
A satellite with mass 6000 kg is orbiting the planet at 2500 km above the planet's
9966 [12]

By the law of universal gravitation, the gravitational force <em>F</em> between the satellite (mass <em>m</em>) and planet (mass <em>M</em>) is

<em>F</em> = <em>G</em> <em>M</em> <em>m</em> / <em>R </em>²

where

<em>• G</em> = 6.67 × 10⁻¹¹ m³/(kg•s²) is the universal gravitation constant

• <em>R</em> = 2500 km + 5000 km = 7500 km is the distance between the satellite and the center of the planet

Solve for <em>M</em> :

<em>M</em> = <em>F R</em> ² / (<em>G</em> <em>m</em>)

<em>M</em> = ((3 × 10⁴ N) (75 × 10⁵ m)²) / (<em>G</em> (6 × 10³ kg))

<em>M</em> ≈ 2.8 × 10¹⁴ kg

6 0
2 years ago
Two long, parallel, current-carrying wires lie in an xy-plane. The first wire lies on the line y = 0.300 m and carries a current
Marrrta [24]

Answer:

Explanation:

Since the wires attract each other , the direction of current will be same in both the wires .

Let I be current in wire which is along x - axis

force of attraction per unit length between the two current carrying wire is given by

\frac{\mu_0}{4\pi}  x \frac{2 I_1\times I_2}{d}

where I₁ and I₂ are currents in the wires and d is distance between the two

Putting the given values

285 x 10⁻⁶ = 10⁻⁷ x \frac{2\times25.5\times I_2}{.3}

I₂ = 16.76 A

Current in the wire along x axis is 16.76 A

To find point where magnetic field is zero due the these wires

The point will lie between the two wires  as current is in the same direction.

Let at y = y , the neutral point lies

k 2 x  \frac{16.76}{y} = k 2 x \frac{25.5}{.3-y}

25.5y = 16.76 x .3 - 16.76y

42.26 y = 5.028

y = .119

= .12 m

3 0
3 years ago
Please answer help me
Andrews [41]
I believe the answer is x
7 0
3 years ago
What is the difference between electric force and electricity
FromTheMoon [43]

Answer:

Electrostatic force is force between two charges separated by distance in space while gravitational force is the force between two masses separated by a distance. Electrostatic force is either repulsive or attractive while gravitational force is always attractive

Explanation:

8 0
3 years ago
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