Answer:
Explanation:
It is given that,
The angle of the hill is 6.00° with respect to the horizontal. Let is the coefficient of kinetic friction between the surface of the hill and the toboggan.
A toboggan slides down a hill and has a constant velocity. On an inclined plane, force of friction will also act.
Force of friction, ...........(1)
Normal force, ............(2)
From equation (1) and (2) :
So, the coefficient of kinetic friction between the surface of the hill and the toboggan is 0.14. Hence, this is the required solution.
Answer:
<u>Assuming b = 9.3i + 9.5j</u> <em>(b = 931 + 9.5 is wrong):</em>
a) a×b = 34.27k
b) a·b = 128.43
c) (a + b)·b = 305.17
d) The component of a along the direction of b = 9.66
Explanation:
<u>Assuming b = 9.3i + 9.5j</u> <em>(b = 931 + 9.5 is wrong)</em> we can proceed as follows:
a) The vectorial product, a×b is:
b) The escalar product a·b is:
c) <u>Asumming (a</u><u> </u><u>+ b)·b</u> <em>instead a+b·b</em> we have:
d) The component of a along the direction of b is:
I hope it helps you!
Let us first calculate heat obtained by the evaporation of 51 g of water.
Given, heat of vaporization of water = 2.4 kJ/ g
∴ Heat obtained by evaporation of 51 g of water = 2.4 × 51 = 122.4 kJ
This is the heat energy available that can be used to cool water from 42°C to 20°C.
Specific heat of water is given by,
Here,
C is the specific heat of water = 4.18 J/gK
Q is the amount of heat = 122400 J
m is the mass of the water that can be cooled.
dt is the change in temperature= 42°C ₋ 20°C = 22°C ( The numerical value will be the same if Kelvin unit is used.)
Substituting the values we get,
m = 1331 g
1331 grams of water can be cooled from 42°C to 20°C by evaporation of 51 g of water.
Answer:
k =
b =
t =
Solution:
As per the question:
Mass of the block, m = 1000 kg
Height, h = 10 m
Equilibrium position, x = 0.2 m
Now,
The velocity when the mass falls from a height of 10 m is given by the third eqn of motion:
where
u = initial velocity = 0
g = 10
Thus
Force on the mass is given by:
F = mg =
Also, we know that the spring force is given by:
F = - kx
Thus
Now, to find the damping constant b, we know that:
F = - bv
Now,
Time required for the platform to get settled to 1 mm or 0.001 m is given by:
Answer:
0.81452 atm
Explanation:
= Initial pressure = 1.43 L
= Volume
= Initial temperature = (28+273.15) K
= Final temperature = (-35+273.15) K
= Final pressure
From the ideal gas law we have
The pressure in the cylinder is 0.81452 atm