2 years ago

Provide two ways that objects can become charged

Physics

1 answer:

kap26 [50]2 years ago

8 0

Answer:

friction, conduction and induction

Explanation:

Had it in class I had it correct hope this helps.

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Calculate the acceleration of a 1400-kg car that stops from 39 km/h "on a dime" (on a distance of 1.7 cm).

Vinil7 [7]

Answer:

$a=-3449.67\frac{m}{s^2}$

Explanation:

The car is under an uniforly accelerated motion. So, we use the kinematic equations. We calculate the acceleration from the following equation:

$v_f^2=v_0^2+2ax$

We convert the initial speed to $\frac{m}{s}$

$39\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=10.83\frac{m}{s}$

The car stops, so its final speed is zero. Solving for a:

$a=\frac{v_0^2}{2x}\\a=-\frac{(10.83\frac{m}{s})^2}{2(1.7*10^{-2}m)}\\a=-3449.67\frac{m}{s^2}$

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dimaraw [331]

C because mass is how much space an object takes up

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All of the following are important reasons to take notes except.

jeka57 [31]

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A LASIK vision-correction system uses a laser that emits 10-ns-long pulses of light, each with 3.0 mJ of energy. The laser beam

lyudmila [28]

<span>P = energy/t = 0.0025/1E-8 = 250000 W
I(ave) = P/A = 250000/(pi*0.425E-3^2) = 4.4056732E11 W/m^2
I(peak) = 2I(ave) = 8.8113463E11 W/m^2
Electric field E = sqrt(I(peak)*Z0) = 1.8219499E7 V/m, where
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Jobisdone [24]

Answer: See photo

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