Answer:
50 g of K₂CO₃ are needed
Explanation:
How many grams of K₂CO₃ are needed to make 500 g of a 10% m/m solution?
We analyse data:
500 g is the mass of the solution we want
10% m/m is a sort of concentration, in this case means that 10 g of solute (K₂CO₃) are contained in 100 g of solution
Therefore we can solve this, by a rule of three:
In 100 g of solution we have 10 g of K₂CO₃
In 500 g of solution we may have, (500 . 10) / 100 = 50 g of K₂CO₃
Answer:
<em>It is a chemical reaction in which the reactants form products and products react together to give reactants back. That means reversible reactions can go in both directions forward as well as backward direction.</em>
The purpose is that it shows you all the elements we know and it arranges them in groups that are also the same kind like Chemistry.
Explanation:
The given following standard cell notation.
Mg(s) | Mg^2+ (aq) || Aq^+(aq) | Aq(s)
Oxidation:
....(1)
Magnesium metal by loosing 2 electrons is getting converted into magnesium cation. Hence, getting oxidized
Reduction:
...(2)
Silver ion by gaining 1 electrons is getting converted into silver metal. Hence, getting reduced.
Overall redox reaction: (1)+2 × (2)
