Percent (%) Composition of CuO
Cu = 1 x 50g - Multiply by one as there is one Cu
O = 1 x 12.5g - Multiply by one as there is one O
CuO = 62.5g
% for Cu = 50g over 62.5 multiplied by 100 = 80%
% for O = 12.5g over 62.5 multiplied by 100 = 20%
Final Answer :
<em>Percent (%) Composition of CuO = </em>80% (Cu) & 20% (O)
Answer:
Number of moles = 3.82 mol
Explanation:
Given data:
Number of moles of CO₂ = ?
Mass of CO₂ = 168.2 g
Solution:
Number of moles = mass/molar mass
Molar mass of CO₂ = 44 g/mol
By putting values,
Number of moles = 168.2 g/ 44 g/mol
Number of moles = 3.82 mol
Answer:
i think it's C
Explanation:
But if it's wrong,im so sorry
Answer:
The major limitations of Newlands' law of octaves were : (i) It was applicable to only lighter elements having atomic masses upto 40 u, i.e., upto calcium. After calcium, the first and the eighth element did not have similar properties
