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Elina [12.6K]
2 years ago
7

If you start with 20 kg of a radioactive isotope, calculate how much of the original isotope is left after one half-life has ela

psed? Write your answer in decimal kg, and as a fraction of the original.
Chemistry
1 answer:
valkas [14]2 years ago
6 0

Answer:

Original price: $

54

Explanation:

cuz

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2 AgNO3(aq) + CaCl2(aq) -----&gt; 2 AgCl(s) + Ca(NO3)2(aq)
yan [13]

5.732 grams of AgCl is formed when 0.200 L of 0.200 M AGNO3 reacts with an excess of CaCl2.

Explanation:

The balanced equation:

2 AgNO3(aq) + CaCl2(aq) -----> 2 AgCl(s) + Ca(NO3)2(aq)

data given:

volume of AgNO3 = 0.2 L

molarity of AgNO3 = 0.200 M

atomic weight of AgCl= 143.32 gram/mole

from the formula, number of moles can be calculated

Molarity = \frac{number of moles}{volume in litres}

number of moles of AgNO3 = 0.04

From the reaction:

2 moles of AgNO3 reacts to form 2 moles of AgCl

0.04 moles of AgNO3 reacts to form x mole of AgCl

\frac{2}{2} = \frac{x}{0.04}

= 0.04 moles of AgCl is formed

mass of AgCl formed is calculated by multiplying number of moles with atomic mass of AgCl

mass of AgCl = 0.04 x 143.32

                       = 5.732 grams of AgCl is formed.

4 0
3 years ago
Okay so I'm a little confused on how this works so I would really appreciate someone helping me figure this out before my big te
tresset_1 [31]
I looked on google cuz i was a lil stumped myself, and it looks like the answer is a. I couldnt find how to solve the equations, sorry
4 0
3 years ago
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