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2 years ago

11

What is 30,000 expressed in scientific notation

1 answer:

Arisa [49]2 years ago

3 0

Answer:

3 x 10^4

Step-by-step explanation:

the decimal is behind the 3 (3.) and you move the decimal 4 times to the right

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Look I have like barely any points can someone help answer this tho

MariettaO [177]

Answer:

3.5

Step-by-step explanation:

These are similar triangles.

BC:AC = BD:AD

6:5 is the ratio.

Then, simply multiply:

4.2 x 5/6 = 3.5

So, x = 3.5!

5 0

3 years ago

What is a name for a marked angle ? Answers to choose from :

katen-ka-za [31]

Answer:

Angles are named in two ways. You can name a specific angle by using the vertex point, and a point on each of the angle's rays. The name of the angle is simply the three letters representing those points, with the vertex point listed in the middle. You can also name angles by looking at their size.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Why is it important to use a device like a random number table in a simulation?

Jet001 [13]

I don’t think it’s the second or third one I’m narrowing it down to the first or maybe fourth

I think the answer is the first one though

5 0

3 years ago

HELLOOOO HELP PLEASE

MA_775_DIABLO [31]

Answer:

$2*log(x)+log(y)$

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

$log_ba^c=c*log_ba$

So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: $log_ba=x\implies b^x=a$

Now if we raise both sides to the power of c, we get the following equation: $(b^x)^c=a^c$

Using the exponential identity: $(x^a)^c=x^{a*c}$

We get the equation: $b^{xc}=a^c$

If we convert this back into logarithmic form we get: $log_ba^c=x*c$

Since x was the basic logarithm we started with, we substitute it back in, to get the equation: $log_ba^c=c*log_ba$

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

$log_b{ac}=log_ba+log_bc$

Now for a quick proof, let's just say: $x=log_ba\text{ and }y=log_bc$

Now rewriting them both in exponential form, we get the equations:

$b^x=a\\b^y=c$

We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

$b^x*b^y=a*c$

Using the exponential identity: $x^{a}*x^b=x^{a+b}$ , we can rewrite the equation as:

$b^{x+y}=ac$

taking the logarithm of both sides, we get:

$log_bac=x+y$

Since x and y are just the logarithms we started with, we can substitute them back in to get: $log_bac=log_ba+log_bc$

Now let's use these identities to rewrite the equation you gave

$log(x^2y)$

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

$log(x^2)+log(y)$

Now using the logarithm of a power to rewrite the log(x^2) we get:

$2*log(x)+log(y)$

3 0

2 years ago

What is 2 1/4 equal to

Crazy boy [7]

Answer:

2.25

Step-by-step explanation:

divide

5 0

3 years ago

Read 2 more answers