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Reika [66]
2 years ago
6

Which of the following is what an elements are made of?

Chemistry
1 answer:
loris [4]2 years ago
6 0

Answer:

An element is made of atoms

Explanation:

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What is the mass of oxygen in 10.0 grams of water
Inessa05 [86]

Answer:

16.00 amu

Explanation:

7 0
3 years ago
Read 2 more answers
Photovoltaic cells convert solar energy into electricity. Calculate the wavelength of light (in nm) required for mercury (Φ =7.2
Sholpan [36]

Answer:

275.3 nm is the wavelength of light required for mercury.

Mercury can not be used to generate electricity from the sun because wavelength at which mercury will emit an electron is smaller than 500 nm.

Explanation:

The wavelength of light required for mercury  to emit an electron.

The wavelength of the radiation = \lambda

Energy required fro mercury to to emit an electron = E

Energy required fro mercury to to emit an electron will the energy if the radiation = E' = 7.22\times 10^{-19} J

E' = E

To calculate the wavelength of light, we use the equation:

E=\frac{hc}{\lambda }

where,

\lambda = wavelength of the light  

h = Planck's constant = 6.626\times 10^{-34} Js

c = speed of light = 3\times 10^8m/s

\lambda =\frac{hc}{E}

=\frac{6.626\times 10^{-34} Js\times 3\times 10^8m/s}{7.22\times 10^{-19} J}

\lambda =2.753\times 10^{-7} m=2.753\times 10^{-7}\times 10^ nm =275.3 nm

Wavelength of the sun light in the visible region = 500 nm

500 nm > 275.3 nm

E\propto \frac{1}{\lambda }

Less energy < more energy

So, this means that mercury can not be used to generate electricity from the sun.

6 0
3 years ago
What is the empirical formula of C20H40
Nat2105 [25]

Answer:

CH2

Explanation:

The empirical formula gives the lowest whole number ratio of the elements. In this case, both subscripts can be divided by 20, hence CH2.

8 0
2 years ago
Which of the following is the major product in the electrophilic addition of HCl to (3S)-2,3-dimethylpent-1-ene?
kvv77 [185]

Answer:

(3S)-2-chloro-2,3-dimethylpentane is produced exclusively.

Explanation:

Electrophilic addition to (3S)-2,3-dimethylpent-1-ene proceeds through a carbocationic intermediate.

In the first step, H^{+} adds onto double bond to produce more stable tertiary carbocation. (protonation)

In the second step, Cl^{-} adds onto carbocation to produce (3S)-2-chloro-2,3-dimethylpentane exclusively.(nucleophilic addition)

So, option (d) is correct.

5 0
3 years ago
Identify the number and type of atoms in the following molecules.
Otrada [13]
Nitrogen atomic# 7 7protons, 7electrons, 7 neutrons

Oxygen atomic# 8 8protons, 8electrons, 8neutrons

Phosphorous atomic# 15 15protons, 15 electrons, 15 neutrons

Sulfur atomic#16 16protons, 16electrons, 16 neutrons
5 0
3 years ago
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